Subtract5x2 + 10x 1 from 6x2 x + 3.

Mathematics

1 answer:

mixer [17]4 years ago

3 0

Answer:

$-6x^{3} +5x^{2} +10x+3$

Step-by-step explanation:

5x^2+10x^1−6x^2x+3

=5x^2+10x+−6x^3+3

Answer:

=−6x^3+5x^2+10x+3

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There are 200 students in eleventh grade high school class. There are 40 students in the soccer team and 50 students in the bask

bekas [8.4K]

Answer:

P(A) = 0.2

P(B) = 0.25

P(A&B) = 0.05

P(A|B) = 0.2

P(A|B) = P(A) = 0.2

Step-by-step explanation:

P(A) is the probability that the selected student plays soccer.

Then:

$P(A)=\dfrac{40}{200}=0.2$

P(B) is the probability that the selected student plays basketball.

Then:

$P(B)=\dfrac{50}{200}=0.25$

P(A and B) is the probability that the selected student plays soccer and basketball:

$P(A\&B)=\dfrac{10}{200}=0.05$

P(A|B) is the probability that the student plays soccer given that he plays basketball. In this case, as it is given that he plays basketball only 10 out of 50 plays soccer:

$P(A|B)=\dfrac{P(A\&B)}{P(B)}=\dfrac{10}{50}=0.2$

P(A | B) is equal to P(A), because the proportion of students that play soccer is equal between the total group of students and within the group that plays basketball. We could assume that the probability of a student playing soccer is independent of the event that he plays basketball.

4 0

4 years ago

Make P the subject.<br> Q = 3P + 2

Ne4ueva [31]

Answer:

P = $\frac{Q-2}{3}$