Answer:
Both figures have a perimeter of 112 inches.
Step-by-step explanation:
Question 5:
You are given a 6-sided shape, but only 4 sides. To find the perimeter, you need to account for the lengths of the other two sides. As all the angles are right angles, the length of the top horizontal side is equal to the combined length of the bottom two horizontal sides. Similarly the length of the left vertical side is equal to the combined length of the right two vertical sides. Because of this, you actually don't need to find the lengths of the unknown sides to answer the question.
This means the perimeter is:
Question 6:
Exactly the same process as above. Just double the longest vertical and horizontal sides (since the sum of the corresponding shorter sides is equal). You'll notice the longest horizontal side is 31, and the longest vertical side is 25...exactly the same as the previous question.
Therefore, the perimeter will again be 112 inches.
These two questions illustrate the difference between area and perimeter. Even though the perimeter of the two shapes is the same, the area of the second shape is larger than the area of the first.
Answer:
The age of Mr. Collins is 30 years and
The model which represent the problem is, The age of Mr. Collins is 3 × 10
Step-by-step explanation:
Given as :
The age of Adam = 10 years
The age of Mr. Collins = x years
The age of Mr. Collins = 3 times the age of Adam
Or, x = 3 × The age of Adam
Or, x = 3 × 10
∴ x = 30
So, The age of Mr. Collins = x years = 30 years
The model which represent the problem is, The age of Mr. Collins = 3 × 10
Hence The age of Mr. Collins is 30 years and
The model which represent the problem is, The age of Mr. Collins = 3 × 10
Answer
0.6=k
This is your answer because the equation is for direct variation is y=kx
You substitute the numbers
Answer:
formulla of perimeter of rectangle
Step-by-step explanation:
perimeter of rectangle=2(l+b)
= 2(7.5+3.25)
=2(11.25)= 22.5
Answer:
- See attachment for table values
- y₁ = y₂ for x = 6
Step-by-step explanation:
In each case, put the x-value in the formula and do the arithmetic. If you're allowed, you can save some time and effort by realizing that the solution (x) will have to be an even number.
y₁ is an integer value for all integer values of x. y₂ is an integer value for even values of x only. y₁ and y₂ will both be integers (and possibly equal) only when x is even.
For example, for x = 6, we have
... y₁ = 3·6 - 8 = 18 -8 = 10
... y₂ = 0.5·6 +7 = 3 +7 = 10
That is, for x = 6, both columns of the table have the same number (10). That is, y₁ = y₂ for x = 6. The solution to the equation
... y₁ = y₂
is
... x = 6.
