Answer:
A
Step-by-step explanation:
plug in y and x, if you want to be sure of each answer
In the case of A) here are the 2 equations, y-2=x+4 and 3x+4=x+6
now plug in what a describes
x=1, y=7
7-2=1+4 and 7=7
Therefore the answer is A
Distance between T(80, 20) and U(20, 60) = sqrt((20 - 80)^2 + (60 - 20)^2) = sqrt((-60)^2 + (40)^2) = sqrt(3600 + 1600) = sqrt(5200) = 72.11 units
Distance between T(80, 20) and V(110, 85) = sqrt((110 - 80)^2 + (85 - 20)^2) = sqrt((30)^2 + (65)^2) = sqrt(900 + 4225) = sqrt(5125) = 71.59
Distance between U(20, 60) and V(110, 85) = sqrt((110 - 20)^2 + (85 - 60)^2) = sqrt((90)^2 + (25)^2) = sqrt(8100 + 625) = sqrt(8725) = 93.41
Therefore, shortest distance for the trip = 71.59 + 93.41 = 165 units.
The answer to question 3 is D. 15(4a+3). And the answer to question 4 is A. 90. Have a great day
Answer: 3rd one
Rearrange the original equation so it fits the model of : ax^2+bx+c=0
Then use the quadratic formula to find all possible answers.
