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gavmur [86]
3 years ago
15

Where do i put a comma in the number 6484649

Chemistry
2 answers:
german3 years ago
8 0
6,484,649 every three numbers from the right
Llana [10]3 years ago
7 0
After every 3 numbers
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5. How many mm are equal to 4.75 x 10-2 m?
liq [111]

Answer:

47.5 mm are equal to 4.75 × 10⁻² m.

Explanation:

Meter and millimeter both are units of length. Millimeter is smaller unit while meter is larger unit. The one meter consist of thousand millimeter or we can say that one thousand millimeters are equal to one meter. In order to convert the meter value into millimeter we have to multiply the values with thousand.

we know that one meter is equal to 1000 millimeter.

1 m = 1000 mm

4.75 × 10⁻² × 1000 = 47.5 mm

47.5 mm are equal to 4.75 × 10⁻² m.

6 0
3 years ago
PLS PLS PLS HELP! TIMED!
Maru [420]
The correct answer is B. if im wrong please correct me if i am wrong
6 0
3 years ago
A scientist is examining a simple multicellular organism with a nucleus and specialized organelles that was found in a moist env
Elza [17]

Answer:Answer: (B) Archaebacteria

Explanation:

Explanation: Archaebacteria, like all prokaryotes, have no membrane bound organelles. This means that the archaebacteria are without nuclei, mitochondria, endoplasmic reticula, lysosomes, Golgi complexes, or chloroplasts. Because these organisms have no nucleus, the genetic material floats freely in the cytoplasm

4 0
4 years ago
Estimate ΔH for the reaction: C2H6(g) + Cl2(g)--> C2H5Cl(g) + HCl(g) given the following average bond energies (in kJ/mol): C
Leno4ka [110]

Explanation:

The reaction equation will be as follows.

    C_{2}H_{6}(g) + Cl_{2}(g) \rightarrow C_{2}H_{5}Cl(g) + HCl(g)

Using bond energies, expression for calculating the value of \Delta H is as follows.

    \Delta H = \sum B.E_{reactants} - \sum B.E_{products}

On reactant side, from C_{2}H_{6} number of bonds are as follows.

C-C bonds = 1

C-H bonds = 6

From Cl_{2}; Cl-Cl bonds = 1

On product side, from C_{2}H_{5}Cl number of bonds are as follows.

C-C bonds = 1

C-H bonds = 5

C-Cl bonds = 1

From HCl; H-Cl bonds = 1

Hence, using the bond energies we will calculate the enthalpy of reaction as follows.

  \Delta H = \sum B.E_{reactants} - \sum B.E_{products}

  =[(1 \times 348 kJ/mol) + (6 \times 414 kJ/mol) + (1 \times 242 kJ/mol)] - [(1 \times 348 kJ/mol) + (5 \times 414 kJ/mol) + (1 \times 327 kJ/mol) + (1 \times 431 kJ/mol)]            = -102 kJ/mol

Thus, we can conclude that change in enthalpy for the given reaction is -102 kJ/mol.

5 0
3 years ago
A solution with a pH of 6.0 is
Romashka-Z-Leto [24]
A solution with a pH of 6 is acidic.  a solution is considered acidic when the pH<7 while a solution is considered basic when the pH>7 (a neutral solution has a pH=7).

I hope this helps.  Let me know if anything is unclear.
7 0
4 years ago
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