If you were presented with 2l of a 2m sucrose stock solution, how many grams of sugar would be in a 100 ml aliquot?

1 answer:

4 0

The 2 L of sucrose stock solution would contain similar concentration with the 100 mL aliquot. Therefore the concentration of aliquot is still 2 M.

The molar mass of sucrose is 342.3 g / mol. Therefore the mass in a 100 mL (0.1 L) aliquot is:

mass = (2 mol / L) * 0.1 L * (342.3 g / mol)

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How many hours will it take for the concentration of methyl isonitrile to drop to 15.0 % of its initial value?

SpyIntel [72]

Answer:

The concentration of methyl isonitrile will become 15% of the initial value after 10.31 hrs.

Explanation:

As the data the rate constant is not given in this description, However from observing the complete question the rate constant is given as a rate constant of 5.11x10-5s-1 at 472k .

Now the ratio of two concentrations is given as

$ln (\frac{C}{C_0})=-kt$

Here C/C_0 is the ratio of concentration which is given as 15% or 0.15.

k is the rate constant which is given as $5.11 \times 10^{-5} \, s^{-1}$

So time t is given as

$ln (\frac{C}{C_0})=-kt\\ln(0.15)=-5.11 \times 10^{-5} \times t\\t=\frac{ln(0.15)}{-5.11 \times 10^{-5} }\\t=37125.6 s\\t=37125.6/3600 \\t= 10.31 \, hrs$