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4 years ago

15

True or false: Most gases behave like ideal gases at many temperatures and pressures

2 answers:

sergejj [24]4 years ago

8 0

Answer:

false

Explanation:

Generally, a gas behaves more like an ideal gas at higher temperature and lower pressure, as the potential energy due to intermolecular forces becomes less significant compared with the particles' kinetic energy, and the size of the molecules becomes less significant compared to the empty space between them.

ladessa [460]4 years ago

4 0

True!!!!!!!!!!!!!!!!!!

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You have two buffered solutions. Buffered solution 1 consists of 5.0 M HOAc and 5.0 M NaOAc; buffered solution 2 is made of 0.05

andre [41]

Answer:

C

Explanation:

The Henderson-Hasselbalch equation relates pH to the concentrations of an weak acid-base conjugate pair as follows:

pH = pKa + log([A⁻]/[HA])

For solution 1, the pH may be expressed as follows:

pH = pKa + log(5.0M/5.0M) = pKa

For solution 2, pH may be expressed as follows:

pH = pKa + log(0.050M/0.050M) = pKa

Thus, the pH values are equal to the pKa in both cases and are the same.

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3 years ago

The rate of effusion of a particular gas was measured and found to be 24.0 mL/min. Under the same conditions, the rate of effusi

Norma-Jean [14]

Answer:

63.6g/mol

Explanation:

Use the equation of effusion:

47.8/24= $\sqrt{x/16.04}$

solve for x you get 63.6g/mol

3 0

3 years ago

Samarium-146 has a half-life of 103.5 million years. After 1.035 billion years, how much samarium-146 will remain from a 205-g s

BaLLatris [955]

Answer : The correct option is, 0.200 g

Solution :

As we know that the radioactive decays follow first order kinetics.

First we have to calculate the rate constant of a samarium-146.

Formula used :

$t_{1/2}=\frac{0.693}{k}$

Putting value of $t_{1/2}$ in this formula, we get the rate constant.

$103.5\times 10^6=\frac{0.693}{k}$

$k=6.6\times 10^{-9}year^{-1}$

Now we have to calculate the original amount of samarium-146.

The expression for rate law for first order kinetics is given by :

$k=\frac{2.303}{t}\log\frac{a}{a-x}$

where,

k = rate constant = $6.6\times 10^{-9}year^{-1}$

t = time taken for decay process = $1.035\times 10^{9}years$

a = initial amount of the samarium-146 = 205 g

a - x = amount left after decay process = ?

Putting values in above equation, we get the value of initial amount of samarium-146.

$6.6\times 10^{-9}=\frac{2.303}{1.035\times 10^{9}}\log\frac{205}{a-x}$

$a-x=0.200g$

Therefore, the amount left of the samarium-146 is, 0.200 g

4 0

4 years ago

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Substances that cause the oxidation of other substances are

svp [43]

<h3>SUBSTANCE</h3>

==============================

$\large \sf\underline{Question:}$

Substances that cause the oxidation of other substances are;

==============================

$\large \sf\underline{Answer:}$

$\qquad \qquad \huge \bold{Option \: B}$

==============================

$\large \sf\underline{Explanation:}$

Substances that cause the oxidation of other substances are oxidizing agents.

==============================

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2 years ago

4. Positive electric charges are always attracted to-____ charges.

kvv77 [185]

Answer: Negatively

Explanation:

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2 years ago

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