Use both!
You want to minimize <em>P</em>, so differentiate <em>P</em> with respect to <em>x</em> and set the derivative equal to 0 and solve for any critical points.
<em>P</em> = 8/<em>x</em> + 2<em>x</em>
d<em>P</em>/d<em>x</em> = -8/<em>x</em>² + 2 = 0
8/<em>x</em>² = 2
<em>x</em>² = 8/2 = 4
<em>x</em> = ± √4 = ± 2
You can then use the second derivative to determine the concavity of <em>P</em>, and its sign at a given critical point decides whether it is a minimum or a maximum.
We have
d²<em>P</em>/d<em>x</em>² = 16/<em>x</em>³
When <em>x</em> = -2, the second derivative is negative, which means there's a relative maximum here.
When <em>x</em> = 2, the second derivative is positive, which means there's a relative minimum here.
So, <em>P</em> has a relative maximum value of 8/(-2) + 2(-2) = -8 when <em>x</em> = -2.
Using synthetic division, you can find the quadratic factor to be
.. 2x^2 -3x +1
That, in turn, factors as
.. (2x -1)(x -1)
So the complete factorization is
.. (2x -1)(x -1)(x +3)
and the zeros are confirmed by a graphing calculator to be
.. x = 1/2, 1, -3
Answer:
8 Minutes
Step-by-step explanation:
since we are trying to find how many minutes have passed we first need to find how much substance was used during the time. we can do that by subtracting the leftover substance from the amount we started with.
666-562 = 104
Now that we know how much substance was used we can then use our conversion rate (13 per minute) and find how many minutes have passed by dividing.
104 / 13 = 8
Answer:
We conclude that the location of A' is: A'(6, 1)
Step-by-step explanation:
Given
To determine:
The location of A'
Translation Rule:
As we have to translate 1 unit left, meaning we need to subtract 1 unit from the x-coordinate of point A(7, 1) to determine the location of A'.
In other words, the translation rule is:
A(x, y) → A'(x-1, y)
as
A(7, 1)
so
A(7, 1) → A'(7-1, 1) = A'(6, 1)
Therefore, we conclude that the location of A' is: A'(6, 1)
Answer:
C) -9p^2 - 5q^2 + 17p - q
Step-by-step explanation:
(10p - 4q^2 - q) - (q^2 - 7p + 9p^2)
10p - 4q^2 - q - q^2 + 7p - 9p^2
10p + 7p - 4q^2 - q^2 -9p^2 - q
17p -5q^2 -9p^2 - q
-9p^2 - 5q^2 + 17p - q