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3 years ago

Classify the expression below.

Mathematics

1 answer:

babymother [125]3 years ago

5 0

Answer:

Step-by-step explanation:

It's a quartic trinomial because its has a fourth degree variable in the expression and only 3 variables in the equation.

2x⁴ - x + 5.

Linear trinomials have 1 degree 3 variables in the monomial. Eg x + y + 2 = 0 is an example of a linear trinomial.

Cubic trinomials have 3 degree and 3 variables in the equation eg = 5x³ + 2x + 1 = 0

Quadratic trinomials is the most common trinomial we deal with everyday eg Ax² + bx + c = 0

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Form a sequence that has two arithmetic means between -1 and 59.

9966 [12]

Answer:

Correct choice is B

Step-by-step explanation:

For the numbers -1 and 59, find the difference 59-(-1):

since 59-(-1)=60 and $\dfrac{60}{3}=20$ (two arithmetic means tells you there will be three intervals), two arithmetic means will be

-1+20=19;
19+20=39.

The only correct sequence is -1, 19, 39, 59.

7 0

3 years ago

Read 2 more answers

Algebra find the unknown digit to make each statement true 2.48>2.4 1>2.463

valentina_108 [34]

We have 2.48>2.4 1>2.463. If we insert a '7' between that 4 and 1, we get:

2.48 > 2.471 >2.463, and this is true.

8 0

2 years ago

The probability that an American CEO can transact business in a foreign language is .20. Twelve American CEOs are chosen at rand

NNADVOKAT [17]

Answer with Step-by-step explanation:

We are given that

The probability that an American CEO can transact business in foreign language=0.20

The probability than an American CEO can not transact business in foreign language= $1-0.20=0.80$

Total number of American CEOs chosen=12

a. The probability that none can transact business in a foreign language= $12C_0(0.20)^0(0.80)^{12}$

Using binomial theorem $nC_r(1-p)^{n-r}p^r$

The probability that none can transact business in a foreign language= $\frac{12!}{0!(12-0)!}(0.8)^{12}=(0.8)^{12}$

b.The probability that at least two can transact business in a foreign language= $1-P(x=0)-p(x=1)=1-((0.8)^{12}+12C_1(0.8)^{11}(0.2))=1-((0.8)^{12}+12(0.8)^{11}}(0.2))$

c.The probability that all 12 can transact business in a foreign language= $12C_{12}(0.8)^0(0.2)^{12}$

The probability that all 12 can transact business in a foreign language= $\frac{12!}{12!}(0.2)^{12}=(0.2)^{12}$

5 0

3 years ago

What is the answer to this 3-(|-4|-|-5|)

Sholpan [36]

60 because all the negatives would cancel out so all you have to do is multiply the numbers

7 0

3 years ago

Gary deposits $1,500 into each of two savings accounts. Account I earns 5% annual simple interest. Account II earns 5% interest

hodyreva [135]

Answer:

$3623.26

Step-by-step explanation:

Given

Each deposit = $1500
Interest rate= 5%
Time = 4 years
Compound number = annual

Simple interest account

B = 1500*(1 + 4*0.05) = 1500*1.2 = $1800

Compound interest account

B = 1500*(1 + 0.05)^4 = $1823.26

Total balance

$1800 + $1823.26 = $3623.26

7 0

3 years ago