A garden is in the shape of a square of length 35 2/5 m. find its (i) perimeter and (ii) area.

Mathematics

1 answer:

Crank3 years ago

3 0

Answer:

perimeter = 56 m

area= 196 m^2

Step-by-step explanation:

perimeter = 4 x sides = 4 x 35(2/5) = 4 x 14 = 56 m

area= sides^2 = (35 x $\frac{2}{5} )^{2}$ = 14^2 = 196 m^2

You might be interested in

The formula for the volume of a cylinder is . What is the approximate volume of two refraction cups? Use 3.14 for pi.

Veronika [31]

Answer:

Is there more information? I need like the height and stuff

5 0

3 years ago

Read 2 more answers

Find the equation of the line that goes through (1, 2) and (3, 4).

Likurg_2 [28]

I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.I have no idea. Just wasting your points like you do to everyone else.

8 0

3 years ago

Graph the equation 4x−4y=12 using the intercepts.

Verdich [7]

X-intercept: (3,0)
Y-intercept: (0,-3)

3 0

4 years ago

Find the value of $ 15,000 at the end of one year if it is invested in an account that has an interest rate of 4.95 % and is com

lora16 [44]

A)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{twelve months, thus}
\end{array}\to &12\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{12}\right)^{12\cdot 1}$

b)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{365 days, thus}
\end{array}\to &365\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{365}\right)^{365\cdot 1}$

c)

$\bf \qquad \textit{Compound Interest Earned Amount}
\\\\
A=P\left(1+\frac{r}{n}\right)^{nt}
\quad 
\begin{cases}
A=\textit{accumulated amount}\\
P=\textit{original amount deposited}\to &\$15000\\
r=rate\to 4.95\%\to \frac{4.95}{100}\to &0.0495\\
n=
\begin{array}{llll}
\textit{times it compounds per year}\\
\textit{four quarters, thus}
\end{array}\to &4\\
t=years\to &1
\end{cases}
\\\\\\
A=15000\left(1+\frac{0.0495}{4}\right)^{4\cdot 1}$

7 0

4 years ago

Y = 3 ( x - 2 )^2 + 5 in standard form

Vlad [161]

Answer:

y=3x^2-12x+17

Step-by-step explanation:

That's what i got

8 0

3 years ago

A garden is in the shape of a square of length 35 2/5 m. find its (i) perimeter and (ii) area.​

A garden is in the shape of a square of length 35 2/5 m. find its (i) perimeter and (ii) area.