To find W⊥, you can use the Gram-Schmidt process using the usual inner-product and the given 5 independent set of vectors.
<span>Define projection of v on u as </span>
<span>p(u,v)=u*(u.v)/(u.u) </span>
<span>we need to proceed and determine u1...u5 as: </span>
<span>u1=w1 </span>
<span>u2=w2-p(u1,w2) </span>
<span>u3=w3-p(u1,w3)-p(u2,w3) </span>
<span>u4=w4-p(u1,w4)-p(u2,w4)-p(u3,w4) </span>
<span>u5=w5-p(u4,w5)-p(u2,w5)-p(u3,w5)-p(u4,w5) </span>
<span>so that u1...u5 will be the new basis of an orthogonal set of inner space. </span>
<span>However, the given set of vectors is not independent, since </span>
<span>w1+w2=w3, </span>
<span>therefore an orthogonal basis cannot be found. </span>
Since x can be any value as long as the denominator equals 0 (it doesn't matter if it's positive or negative), we have to figure out when x^2=0, which is when x=0. Therefore, the domain is (-inf, 0) U (0, inf)
Answer:
when we put 1 from a2 we can say that a2 equal to 2 because 2.5^n-1= 2
Step-by-step explanation:
answer is b
Answer:
150 regular loaves
125 loaves with extra sugar
100 loaves with extra bananas.
Step-by-step explanation:
Let R represent loaves of regular bread, S represent loaves with extra sugar, and B represent loaves with extra bananas. If they have 1200 bananas, 1050 cups of sugar, and 1075 cups of flour available, the number of each type of bread that Angie and Brian can make are given by the following system of equations:

Solving the linear system:

They should make 150 regular loaves, 125 loaves with extra sugar, and 100 loaves with extra bananas.
The given polynomial is f(x) = x² - 2x - 6
Rewrite the function by completing the square.
f(x) = [x² - 2x] - 6
= [(x-1)² - 1] - 6
= (x-1)² - 7
In vertex form,
f(x) = (x-1)² - 7
The vertex is located at (1, -7).
Because the leading coefficient is +1, the curve opens upward.
Answer: f(x) = (x - 1)² - 7