Question

What is the equation of a line in point slope form that oases trough (-2,-6) and has a slope of 1/3

Answer 1

Answer:

y + 6 = $\frac{1}{3}$(x + 2)

Step-by-step explanation:

The equation of a line in point- slope form is

y - b = m(x - a)

where m is the slope and (a, b) a point on the line

Here m = $\frac{1}{3}$ and (a, b) = (- 2, - 6 ) , thus

y - (- 6) = $\frac{1}{3}$(x - (- 2) ) , that is

y + 6 = $\frac{1}{3}$(x + 2)