Let's solve for both of the acute angles for the purpose of checking our work at the end with angle A being the top angle and angle B being the one on the base of the triangle (that's not the 90 degrees one). Determining whether to use sin/cos/tan comes from SOH-CAH-TOA.

A = cos^-1 (2√6/2√15)

However, you need to move the radical out of the denominator by multiplying √15 to the numerator and denominator. You should come up with (2√90)/30. So,

A = cos^-1 (2√90/30) = 50.768 degrees.

B = sin^-1 (2√90/30) = 39.231 degrees.

Now, we can check the work by adding the 2 angles to 90 and, if it comes to 180, it's right.

cos^-1 (2√90/30) + sin^-1 (2√90/30) + 90 = 180.

If you have any questions on where I got a formula or any step, feel free to ask in the comments!

8 0

3 years ago

Erin buys a bag of peanuts that weighs 3/4 of a pound.Later that week, the bag is 2/3 full.How much does the bag of peanuts weig

dusya [7]

So he started with 3/4 lb and ended up with 2/3 of that so 2/3 of 3/4

'of' can be roughly translated as multiply

so 2/3 times 3/4 =6/12=1/2 lb left

or you know that there are 3 out of 4 parts pound left so 2 out of 3 parts of nuts is = 2/4 or 1/2 lb

6 0

3 years ago