Answer: A
Step-by-step explanation: Because it can be simplified twice.
Answer:
option D
D. x = 5, y = 2
Step-by-step explanation:
Given in the question two equation,
Equation 1
5.3x + y = 28.5
Equation 2
4.2x + 3.1y = 27.2
rearrange equation 1 in terms of y
y = 28.5 - 5.3x
Substitute the value of y in equation 2
<h3>4.2x + 3.1(28.5 - 5.3x) = 27.2</h3>
4.2x + 88.35 - 16.43x = 27.2
4.2x - 16.43x = 27.2 - 88.35
-12.23x = -61.15
x = 61.15/12.23
x = 5
put value of x in any of the equation
<h3>5.3(5) + y = 28.5</h3>
y = 28.5 - 26.5
y = 2
Answer:
- time: t = -0.3
- minimum: v = 0.55
Step-by-step explanation:
For quadratic ax^2 + bx + c, the extreme value is found at x=-b/(2a). For your quadratic, the minimum is found at ...
t = -(3)/(2(5))
t = -0.3 . . . . . time of minimum velocity
__
The value of velocity at that time is ...
v = 5(-0.3)^2 +3(-0.3) +1 = 5(.09) -.9 +1
v = 0.55 . . . . . value of minimum velocity