Is this the entire question?
Answer:
hello your question has some missing information attached below is the missing information
answer : 112 black balls
Step-by-step explanation:
Given data:
Each bag contains ; 10 balls
Total number of ball = 100 balls
<u>first: calculate the number of Black balls to be picked from the three bags</u>
From bag 1 = 0.4 * 0.35 * 10 = 1.4 balls
From bag 2 = 0.8 * 0.45 * 10 = 3.6 balls
From bag 3 = 0.3 * 0.2 * 10 = 0.6 ball
Total black balls picked = 5.6
∴ percentage of black balls picked given that each bag contains 10
5.6 / 10 * Total balls available = 56 balls = 56% of 100 balls
Hence If the player plays this game 200 times the number of black balls he will pick = 56% * 200 = 112 balls
Answer: it will take 13.3 years
Step-by-step explanation:
We would apply the formula for determining compound interest which is expressed as
A = P(1+r/n)^nt
Where
A = total amount in the account at the end of t years
r represents the interest rate.
n represents the periodic interval at which it was compounded.
P represents the principal or initial amount deposited
From the information given,
P = 6000
A = 10000
r = 4% = 4/100 = 0.04
n = 12 because it was compounded 12 times in a year.
Therefore,.
10000 = 6000(1 + 0.04/12)^12 × t
10000/6000(1 + 0.0033)^12t
1.67 = 1.0033^12t
Taking log to base 10 of both sides, it becomes
Log 1.67 = 12tLog 1.0033
0.223 = 12t × 0.0014
0.223 = 0.0168t
t = 0.223/0.0168
t = 13.3 years
If a rational number after dot "like 5.52") is smaller than 5(half) , then you assume the first number before that dot stuff :p
For example:
-》11,2 =11
-》 4.19= 4
-》2,2 = 2
etc
But if it's bigger than 5 or equals 5 , u assume the first number before that dot stuff +1
For example :
-》5.5 =6
-》3.9=4
-》225.7= 226
etcetc
so the answer is:;;
5.52 --》 52 is bigger than a half (50) so ur gonna assume like 6
1,6 --》(it equals with 1.60 too)
6 is bigger than 5 so ur gonna assume 2
6÷2 =3
Hope it helps! :))
#MissionExam001
Answer : P(second resistor is 100ω , given that the first resistor is 50ω) is given by
![\frac{1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D)
Explanation :
Since we have given that
Total number of resistors =15
Number of resistors labelled with 50ω = 12
Number of resistors labelled with 100ω =3
Let A: Event getting resistor with 50ω
B: Event getting resistor with 100ω
Since A and B are independent events .
So,
![P(A\cap B)=P(A).P(B)](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3DP%28A%29.P%28B%29)
Now, According to question , we can get that
![P(A)= \frac{12}{15}=\frac{4}{5}\\\\P(B)=\frac{3}{15}=\frac{1}{5}](https://tex.z-dn.net/?f=P%28A%29%3D%20%5Cfrac%7B12%7D%7B15%7D%3D%5Cfrac%7B4%7D%7B5%7D%5C%5C%5C%5CP%28B%29%3D%5Cfrac%7B3%7D%7B15%7D%3D%5Cfrac%7B1%7D%7B5%7D)
So,
![P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\frac{4}{5}\times \frac{1}{5}\\\\P(A\cap B)=\frac{4}{25}](https://tex.z-dn.net/?f=P%28A%5Ccap%20B%29%3DP%28A%29.P%28B%29%5C%5C%5C%5CP%28A%5Ccap%20B%29%3D%5Cfrac%7B4%7D%7B5%7D%5Ctimes%20%5Cfrac%7B1%7D%7B5%7D%5C%5C%5C%5CP%28A%5Ccap%20B%29%3D%5Cfrac%7B4%7D%7B25%7D)
So, by using the conditional probability , which state that
![P(B\mid A)=\frac{P(A\cap B)}{P(A)}](https://tex.z-dn.net/?f=P%28B%5Cmid%20A%29%3D%5Cfrac%7BP%28A%5Ccap%20B%29%7D%7BP%28A%29%7D)
![P(B\mid A)=\frac{\frac{4}{25}}{\frac{4}{5}}\\\\P(B\mid A)=\frac{5}{25}\\\\P(B\mid A)=\frac{1}{5}](https://tex.z-dn.net/?f=P%28B%5Cmid%20A%29%3D%5Cfrac%7B%5Cfrac%7B4%7D%7B25%7D%7D%7B%5Cfrac%7B4%7D%7B5%7D%7D%5C%5C%5C%5CP%28B%5Cmid%20A%29%3D%5Cfrac%7B5%7D%7B25%7D%5C%5C%5C%5CP%28B%5Cmid%20A%29%3D%5Cfrac%7B1%7D%7B5%7D)
So, P(second resistor is 100ω , given that the first resistor is 50ω) is given by
![\frac{1}{5}](https://tex.z-dn.net/?f=%5Cfrac%7B1%7D%7B5%7D)