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topjm [15]
2 years ago
5

Someone give me the answer

Mathematics
1 answer:
Butoxors [25]2 years ago
4 0

a function that model the number of people that receives email in week t  is P(t)=37(4)^{\frac{t}{9.1}} .

<u>Step-by-step explanation:</u>

Here we have , Tobias sent a chain letter to his friends . The number of people who receives the email increases by a factor of 4 in every 9.1 weeks , and can be modeled by a function P, which depends on the amount of time t weeks . Tobias initially sent letter to 37 friends . We need to write a function that model the number of people that receives email in week t . Let's find out:

Basically it's an exponential function as

f(x) = e^{ax} , In question initial value is 37 & and for every 9.1 weeks there is increase in people by a factor of 4 i.e.

⇒ P(t)=37(4)^t

But , wait ! People increase in every 9.1 weeks not every week so modified equation will be :

⇒ P(t)=37(4)^{\frac{t}{9.1}}

Therefore , a function that model the number of people that receives email in week t  is P(t)=37(4)^{\frac{t}{9.1}} .

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Assume that when adults with smartphones are randomly​ selected, 52​% use them in meetings or classes. If 14 adult smartphone us
emmasim [6.3K]

The probability that fewer than 4 of then use their smart phones in meetings  or classes is 0.00030243747.

Step-by-step explanation:

Fewer than 4 means ,less than 4 which is any number less than 4 and not including 4. This is 3, 2,1 and 0. So you find the probability that exactly 3 of then use their smart phone, exactly 2 of them use their smart phones, exactly 1 of them use his/her smart phone and none of them.

Given that 52% use smartphones in meetings and classes =0.52

Thus the remaining 48% do not use smartphones in meetings and classes=0.48

For C(14,3) you will have "14 chose 3", number of ways of choosing 3 out of 14'

=(0.52)³ *(0.48)⁹=0.00019018714

For C(14,2) you will have "14 chose 2", number of ways of choosing 2 out of 14

=(0.52)²*(0.48)¹²=0.00004044841

For C(14,1) you will have "14 chose 1", number of ways of choosing 1 out of 14

=(0.52)¹*(0.48)¹³=0.000037337

For  C(14,0) you will have "14 chose 0", number of ways of choosing 0 out of 14

=(0.52)⁰*(0.48)¹⁴=1*0.00003446492=0.00003446492

The probability that fewer than 4 of them use their smartphones in meetings or classes will be

0.00019018714 +0.00004044841+0.000037337+ 0.00003446492=0.00030243747

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