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Afina-wow [57]
2 years ago
10

unction f(x) = (x − 4)(x − 2) is shown. On a coordinate plane, a parabola opens up. It goes through (2, 0), has a vertex at (3,

negative 1), and goes through (4, 0). What is the range of the function? all real numbers less than or equal to 3 all real numbers less than or equal to −1 all real numbers greater than or equal to 3 all
Mathematics
1 answer:
Olegator [25]2 years ago
9 0

9514 1404 393

Answer:

  (d)  all real numbers greater than or equal to -1

Step-by-step explanation:

The y-value of the vertex at (3, -1) is the minimum of the function. All y-values equal to or greater than -1 are in the range of the function.

  y ≥ -1

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Find the perimeter of a square with sides of 61 +5.
KATRIN_1 [288]

Answer:

264

Step-by-step explanation:

the perimeter of a square with sides of 61+5 is 264

6 0
3 years ago
Read 2 more answers
The perimeter of a rectangular garage is 44 meters. the garage is 12 meters long. how wide is it?
wel
Hello!

To find the perimeter you do 2l + 2w.

l is length
w is width

put in the values we know

2(12) + 2w = 44

Combine like terms

24 + 2w = 44

Subtract 24 from both sides

2w = 20

Divide both sides by 2

w = 10

The answer is 10 meters

Hope this helps!
8 0
2 years ago
Yolanda has a box that contains 8 3/4 dozen beads. She uses 3 1/4 dozen beads for a necklace and 1 3/4 dozen beads for a bracele
Artyom0805 [142]

Answer:

The answer is a bit c d

3 0
2 years ago
Read 2 more answers
Dinesh thinks that the point (1,3) is on the line y = 4x - 2.
olga_2 [115]

To see if the point is on the line, plug in one of the point values to see if it equals out.

y = 4x - 2         I will plug in 1 for x to see if y does = 3

y = 4(1) - 2

y = 4 - 2

y = 2           so (1, 2)

Dinesh is not correct because the point on the line when x = 1 is (1, 2) not (1, 3)

8 0
2 years ago
A population of insects grows exponentially, as shown in the table. Suppose the increase in population continues at the same rat
Ivanshal [37]

We are told that a population of insects grows exponentially and we are given a table of data about insect population growth. We are asked to find population of insects at the end of week 11.        

The initial insect population is 20 and at the end of 1st week population increases to 30.

Let us find growth percentage of insect  population,

\text{Growth percentage}=\frac{\text{Difference}}{Actual} \cdot100

\text{Growth percentage}=\frac{\text{30-20}}{20} \cdot100

\text{Growth percentage}=\frac{\text{10}}{20} \cdot100

\text{Growth percentage}=0.5 \cdot100=50

We can see that insect population is growing at rate of 50% per week.

Now let us write an exponential function for our population.

P(w)=20(1+0.50)^{w}, where P(w) represents population at the end of w weeks.

Let us substitute w=11 in our function to find insect population at the end of 11 weeks.

P(11)=20(1+0.50)^{11}

P(11)=20(1.50)^{11}

P(11)=20\cdot 86.49755859375

P(11)=1729.951171875\approx 1730

Therefore, population of insects at the end of 11th week will be 1730.  



7 0
3 years ago
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