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Furkat [3]
3 years ago
14

Circle A is shown with a central angle marked 37 degrees and the radius marked 10 inches.

Mathematics
1 answer:
Greeley [361]3 years ago
4 0

Answer:

Hello! Your answer would be, D)π(37in) 5 over 360

Step-by-step explanation:

Hope I helped! Brainiest plz!♥ Have a nice afternoon! Hope you make a 100%! -Amelia

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Find the derivative of f(x) = negative 9 divided by x at x = -4. (6 points) 4 divided by 9 16 divided by 9 9 divided by 16 9 div
Len [333]

Answer:

9/16

Step-by-step explanation:

f(x)=-\frac{9}{x}

f(x)=-9x^{-1}

Derivative rule:

f(x)=x^{n} \\

\frac{df}{dx}=nx^{n-1}

Here, n=-1, so

\frac{df}{dx}=(-9)(-1)x^{-2} =\frac{9}{x^{2} }

Evaluating this at x=-4 gives 9/16

5 0
3 years ago
Read 2 more answers
In an insect colony there are 270 insects after 9 days. If there were initially 80 insects how long will it take the population
Semenov [28]

Answer:

The time it will take the population to grow to 800 insects is 17 days.

Step-by-step explanation:

The growth function of the insects is exponential.

The exponential growth function is:

y=a(1+r)^{t}

Here,

<em>y</em> = final value

<em>a</em> = initial value

<em>r</em> = growth rate

<em>t</em> = time taken

It is provided that there were 270 insects after 9 days and initially there were 80 insects.

Compute the value of <em>r</em> as follows:

y=a(1+r)^{t}\\\\270=80(1+r)^{9}\\\\3.375=(1+r)^{9}\\\\\ln(3.375)=9\cdot \ln(1+r)\\\\0.135155=\ln(1+r)\\\\1+r=1.14471\\\\r=0.145

Now, compute the time it will take the population to grow to 800 insects as follows:

800=80(1+0.145)^{t}\\\\10=(1.145)^{t}\\\\\ln(10)=t\cdot \ln(1.145)\\\\t=17.00522\\\\t\approx 17

Thus, the time it will take the population to grow to 800 insects is 17 days.

7 0
3 years ago
Can you guys help my teacher makes no sense
LiRa [457]
What makes no sense I don't get it what it means plus look it up if can
7 0
3 years ago
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a jogger ran 3 miles due east of his house. then he ran 5 miles at a heading of 30 east of north. how far is he from his house a
Jobisdone [24]
Let's say her speed was x miles/hour during the first 3 miles runThen, time = distance/speedt1 = 3/x       eq1 In the next 4 miles run, her speed = x-1 miles/hourTime taken:t2 = 4/(x-1)      eq2 Now, total time:t1 + t2 = 1 3/5 hourssubstitute t1 and t2 from eqs. 1 and 2 3/x + 4/(x-1) = 1 3/5=> 3/x + 4/(x-1) = 8/5
=> 3(x-1) + 4x = 8x(x-1)/5=> 35x - 15 = 8x2 - 8x=> 8x2 - 43x + 15 = 0=> (8x-3)*(x-5) = 0=> x = 3/8 or 5 miles/hourx can not be 3/8 miles/hour because in that case, the speed during 4 miles run would be 3/8-1 = negative numberi.e. speed during 3 miles segment = 5 miles/hourand speed during 4 miles segment = 5-1 = 4 miles/hour
5 0
3 years ago
How do I solve for x?<br><br> -7x-3x+2= -8x-8
Delicious77 [7]

-7X -3X+8X=-8-2

-2X=-10

X=5

4 0
3 years ago
Read 2 more answers
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