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Fofino [41]
3 years ago
8

Which of the equations below represents a line perpendicular to the x-axis?

Mathematics
2 answers:
Allushta [10]3 years ago
5 0

Answer:

Option B

Step-by-step explanation:

we know that

A line perpendicular to the x-axis is a line parallel to the y-axis

so

the equation of the line is of the form x=(+/-)a

The slope of the line is undefined

where

a is a real number

therefore

x=6 is a line perpendicular to the x-axis

leva [86]3 years ago
4 0

Answer:

B. x = 6

Step-by-step explanation:

The x-axis is the line of 0 = y [<em>horizontal line</em>], therefore the ONLY live perpendicular to that would be x = 6, which is a <em>vertical</em><em> </em><em>line</em>, giving you a <em>right</em><em> </em><em>angle</em><em> </em>in the centre.

I am joyous to assist you anytime.

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<h2>Step-by-step explanation:</h2>

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In our case, the first term has a negative exponent and it is at the numerator. We therefore move it to the denominator and change the negative exponent to  positive as follows;

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i. Rewrite as follows;

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ii. The second term has a negative exponent, therefore swap its position and change the negative exponent to a positive one.

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iii. Now solve by cancelling out common terms in the numerator and denominator. So we have;

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\frac{4x^4}{y^3}

Therefore, 2x³y⁻³ . 2x = \frac{4x^4}{y^3}

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