For a probability distribution to be represented, it is needed that P(X = 0) + P(X = 1) = 0.44. Hence one possible example is:
<h3>What is needed for a discrete random variable to represent a probability distribution?</h3>
The sum of all the probabilities must be of 1, hence:
P(X = 0) + P(X = 1) + P(X = 3) + P(X = 4) + P(X = 5) = 1.
Then, considering the table:
P(X = 0) + P(X = 1) + 0.15 + 0.17 + 0.24 = 1
P(X = 0) + P(X = 1) + 0.56 = 1
P(X = 0) + P(X = 1) = 0.44.
Hence one possible example is:
More can be learned about probability distributions at brainly.com/question/24802582
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Assuming that this is just on a 2-D coordinate plane, we must convert the expressions on to a 3-D plane since translation cannot be done on a 2-D plane. This is done by adding a dummy coordinate that does not change. Let us use "1" for this case.
Matrix:
| 0 0 -2 |(x) = (x - 2)
<span>| 0 0 4 |(y) = (y + 4)
</span><span>| 0 0 1 |(1) = 1</span>
