I wish I could help you but Im doing this so i can ask sum
Answer:
Step-by-step explanation:
Represent the length of one side of the base be s and the height by h. Then the volume of the box is V = s^2*h; this is to be maximized.
The constraints are as follows: 2s + h = 114 in. Solving for h, we get 114 - 2s = h.
Substituting 114 - 2s for h in the volume formula, we obtain:
V = s^2*(114 - 2s), or V = 114s^2 - 2s^3, or V = 2*(s^2)(57 - s)
This is to be maximized. To accomplish this, find the first derivative of this formula for V, set the result equal to 0 and solve for s:
dV
----- = 2[(s^2)(-1) + (57 - s)(2s)] = 0 = 2s^2(-1) + 114s - 2s^2
ds
Simplifying this, we get dV/ds = -4s^2 + 114s = 0. Then either s = 28.5 or s = 0.
Then the area of the base is 28.5^2 in^2 and the height is 114 - 2(28.5) = 57 in
and the volume is V = s^2(h) = 46,298.25 in^3
Answer:
The reasonable prediction for successful rolls is 4.
Step-by-step explanation:
Assuming the rolling cube is a fair 6 sided cube, so the probability of success of one roll is given as


The total success is given as

For 24 rolls it is given as

So the reasonable prediction for successful rolls is 4.
Answer:
You are mulitplying the last number by two. The next two terms are 32 and 64.
Step-by-step explanation:
Since x dollars is the total monthly sales Paul makes when his sales exceed 20,000 dollars, then the function f(x) should add x dollars and $20,000. The answer is B. x+20,000.
Assuming that x dollars is still the sales after gaining $20,000, then 15 percent of x is modeled by B. 0.15x.