The equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 1
<h3>Equation of a line</h3>
A line is the distance between two points
Given the equation of a line expressed as 10x + 2y = -2. Determine the slope
2y = -10x -2
y = -5x - 1
Slope of the line is -5
The equation of a line in point-slope form is y - y1 = m(x-x1)
Substitute the point and the slope of the parallel line
y - 12 = -5(x - 0)
y - 12 = -5x
y = -5x + 12
Hence the equation, in slope-intercept form, of the line that is parallel to the given line and passes through the point (0, 12) is y = -5x + 12
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(₋4)²
how i got it -
1st i used the sum-product pattern
x² - 8x + 16
x² -4-4+16
then, found the common fact from the two pairs
x² - 4 - 4 + 16
(-4) - 4(-4)
rewrite in factored form
(x-4)-4(-4)
(-4) (-4)
combine to a square
(-4) (-4)
Answer:
1 1/4
Step-by-step explanation:
trust my guy just keep adding until you get 1 cup of milk
Answer:
It is 
(12 × 4) = 24
Step-by-step explanation:
(base × height) = area of triangle
(12 × 4) = area
area = 24
Answer: D
Step-by-step explanation:
Look at the exponents first and order them from least to greatest
