Question

Which is the axis of symmetry of a parabola with equation x^2=-4y?

Answer 1

Answer:

The axis of symmetry is $x=0$

Step-by-step explanation:

we know that

The equation of a vertical parabola into vertex form is equal to

$y=a(x-h)^{2} +k$

where

(h,k) is the vertex of the parabola

and the axis of symmetry is the x-coordinate of the vertex

$x=h$

In this problem we have

$x^{2} =-4y$

The vertex is the origin

therefore

the axis of symmetry is

$x=0$

Answer 2

Y=a(x-h)²+k

x=h is the axis of symmetry
so
-4y=x²
times both sides by -1/4
y=(-1/4)x²
y=(-1/4)(x-0)²+0
axis of symmetry is x=0

3rd option