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musickatia [10]
3 years ago
8

Thank you for taking the time to look at my question

Mathematics
2 answers:
Deffense [45]3 years ago
8 0

Answer:

I think it's B but im not sure

hope this helps

have a good day :)

Step-by-step explanation:

k0ka [10]3 years ago
5 0

Answer and Step-by-step explanation:

The functions f(x) is being put into the function of g(x).

\frac{2x + 3}{4}

\frac{1}{2} x + \frac{3}{4}

<u>Our answer is Answer choice 2.</u>

<u></u>

<u></u>

<em><u>#teamtrees #PAW (Plant And Water)</u></em>

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What is 7a^{2} - a^{2} + 16
prohojiy [21]

Answer:can u pls help answer my question 4d+15 is greater than or equal to -1

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Hadley paddled a canoe 2/3 mile in 1/4 hour. How fast did Hadley paddle, in miles per hour?
irina [24]

Answer:

d

Step-by-step explanation:

Hadley paddled a canoe 2/3 mile in 1/4 hour. it will be 4 times more in an hour because 1/4*4=4/4=1. 2/3*4=8/3=2 2/3

8 0
3 years ago
Divide. 1/4 ÷ 3=<br>help​
Aleonysh [2.5K]
1/4/3 = 1/12
hope you understand
6 0
3 years ago
2x^2+3x-2, a=0 How do I find the derivative?
Ghella [55]

You can use the definition:

\displaystyle f'(x) = \lim_{h\to0}\frac{f(x+h)-f(x)}h

Then if

f(x) = 2x^2+3x-2

we have

f(x+h) = 2(x+h)^2+3(x+h) - 2 = 2x^2 + 4xh+2h^2+3x+3h-2

Then the derivative is

\displaystyle f'(x) = \lim_{h\to0}\frac{(2x^2+4xh+2h^2+3x+3h-2)-(2x^2+3x-2)}h \\\\ f'(x) = \lim_{h\to0}\frac{4xh+2h^2+3h}h \\\\ f'(x) = \lim_{h\to0}(4x+2h+3) = \boxed{4x+3}

I'm guessing the second part of the question asks you to find the tangent line to <em>f(x)</em> at the point <em>a</em> = 0. The slope of the tangent line to this point is

f'(0) = 4(0) + 3 = 3

and when <em>a</em> = 0, we have <em>f(a)</em> = <em>f</em> (0) = -2, so the graph of <em>f(x)</em> passes through the point (0, -2).

Use the point-slope formula to get the equation of the tangent line:

<em>y</em> - (-2) = 3 (<em>x</em> - 0)

<em>y</em> + 2 = 3<em>x</em>

<em>y</em> = 3<em>x</em> - 2

5 0
3 years ago
Pls if anyone knows the answer with work included/steps that will be greatly appreciated :)
dimaraw [331]

Answer:

1. Option D. 15x²

2. Option C. 3

Step-by-step explanation:

1. Determination of the area of one section.

Length (L) of one section = 25x/5 = 5x

Width (W) of one section = 3x

Area (A) of one section =?

The area of one section can be obtained as follow:

Area (A) = Length (L) × Width (W)

A = L × W

A = 5x * 3x

A = 15x²

Thus, the area of one section is 15x²

2. Determination of the expressions that are equivalent to (p²)³.

We'll begin by simplifying (p²)³. This can be obtained as follow:

(p²)³ = p²*³

(p²)³ = p⁶

Next we shall compare each expression given in the question above to see which will be the same as p⁶.

p × p × p × p × p × p = p¹⁺¹⁺¹⁺¹⁺¹⁺¹

p × p × p × p × p × p = p⁶

p² × p² × p² = p²⁺²⁺²

p² × p² × p² = p⁶

p² × p³ = p²⁺³

p² × p³ = p⁵

Thus,

p² × p³ ≠ p⁶

p⁵ ≠ p⁶

p⁶ = p⁶

SUMMARY

p × p × p × p × p × p = p⁶ = (p²)³

p² × p² × p² = p⁶ = (p²)³

p⁶ = (p²)³

Therefore, 3 expressions are equivalent to (p²)³. Option C gives the correct answer to the question.

6 0
3 years ago
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