I will mark brainlist please help what is the vertex of the parabola

If men's heights are normally distributed with mean 68 and standard deviation 3.1 inches, and women's heights are normally distr

stira [4]

Answer:

the probability that the woman is taller than the man is 0.1423

Step-by-step explanation:

Given that :

the men's heights are normally distributed with mean $\mu$ 68

standard deviation $\sigma$ = 3.1

And

the women's heights are normally distributed with mean $\mu$ 65

standard deviation $\sigma$ = 2.8

We are to find the probability that the woman is taller than the man.

For woman now:

mean $\mu$ = 65

standard deviation $\sigma$ = 2.8

$P(x > 68 ) = 1 - p( x< 68)$

$\\ 1 -p \ P[(x - \mu ) / \sigma < (68-25)/ 2.8]$

= 1-P (z , 1.07)

Using z table,

= 1 - 0.8577

= 0.1423

Thus, the probability that the woman is taller than the man is 0.1423

6 0

3 years ago

Scott and Letitia are brother and sister. After dinner, they have to do the dishes, with one washing and the other drying. They

ehidna [41]

Answer:

The probability that Scott will wash is 2.5

Step-by-step explanation:

Given

Let the events be: P = Purple and G = Green

$P = 2$

$G = 3$

Required

The probability of Scott washing the dishes

If Scott washes the dishes, then it means he picks two spoons of the same color handle.

So, we have to calculate the probability of picking the same handle. i.e.

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

This gives:

$P(G_1\ and\ G_2) = P(G_1) * P(G_2)$

$P(G_1\ and\ G_2) = \frac{n(G)}{Total} * \frac{n(G)-1}{Total - 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{3-1}{5- 1}$

$P(G_1\ and\ G_2) = \frac{3}{5} * \frac{2}{4}$

$P(G_1\ and\ G_2) = \frac{3}{10}$

$P(P_1\ and\ P_2) = P(P_1) * P(P_2)$

$P(P_1\ and\ P_2) = \frac{n(P)}{Total} * \frac{n(P)-1}{Total - 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{2-1}{5- 1}$

$P(P_1\ and\ P_2) = \frac{2}{5} * \frac{1}{4}$

$P(P_1\ and\ P_2) = \frac{1}{10}$

<em>Note that: 1 is subtracted because it is a probability without replacement</em>

So, we have:

$P(Same) = P(G_1\ and\ G_2) + P(P_1\ and\ P_2)$

$P(Same) = \frac{3}{10} + \frac{1}{10}$

$P(Same) = \frac{3+1}{10}$

$P(Same) = \frac{4}{10}$

$P(Same) = \frac{2}{5}$

8 0

3 years ago

In a freshman class of 80 students,22 students take Consumer Education,20 students take French,and 4 students take both.Which eq

MAXImum [283]

<h3>Answer: Choice C</h3>

P = 11/40 + 1/4 - 1/20

=========================================================

Explanation:

The formula we use is

P(A or B) = P(A) + P(B) - P(A and B)

In this case,

P(A) = 22/80 = 11/40 = probability of picking someone from consumer education
P(B) = 20/80 = 1/4 = probability of picking someone taking French
P(A and B) = 4/80 = 1/20 = probability of picking someone taking both classes

So,

P(A or B) = P(A) + P(B) - P(A and B)

P(A or B) = 11/40 + 1/4 - 1/20

which is why choice C is the answer

----------------

Note: P(A and B) = 1/20 which is nonzero, so events A and B are not mutually exclusive.

6 0

3 years ago

What is the value of a

Diano4ka-milaya [45]

Answer: Multiplying 3x and -x we obtain A= -3x^2

8 0

3 years ago

Quadrilateral army is rotated 90° about the origin

nevsk [136]

Sorry I am late but the I think it is this, I don’t know the answer but here is what I know. answer is: Imagine a rectangle that has one vertex at the origin and the opposite vertex is A. Now that you can see the image of A(3,4) under the rotation is A’(-4,3). It is easier to rotate the points that lie on the axes, and these help us find the image of A.
POINT: (3,0) (0,4) (3,4)
IMAGE (3,0) (-4,0) (-4,3)

8 0

2 years ago