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Harman [31]
3 years ago
9

The stack on the left is made up of 15 pennies, and the stack on the right is also made up of 15 pennies. If the volume of the s

tack of pennies on the left is 375 mm3, what is the volume of the stack of pennies on the right in cubic millimeters? (Hint: only enter numerals in the answer blank) (4 points)
Two stacks of pennies are shown. The stack of pennies on the left form a right cylinder while the stack of pennies on the right
Mathematics
2 answers:
svetoff [14.1K]3 years ago
4 0

Answer:

The correct answer to this question is 375. mm^3. I hope this helps, like actually.

Step-by-step explanation:

Please report the second answer for posting adult content.

Kruka [31]3 years ago
3 0

Answer:

375

Step-by-step explanation:

i was on the test looking for an answer and figured it out

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xxMikexx [17]

Answer:

ytyu

Step-by-step explanation:

8 0
4 years ago
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What is the value of the expression (25-7)x2 divided by 4+2
fomenos

\huge\text{Hey there!}

\mathsf{\dfrac{(25-7)(2)}{4}+2}

\mathsf{25-7=\bf 18}

\mathsf{\dfrac{\bold{18}(2)}{4}+2}

\mathsf{18(2)= \bf 36}

\mathsf{\dfrac{\bold{36}}{4}+2}

\mathsf{\dfrac{36}{4}=\bf 9}

\mathsf{\bold{9}+2 }

\bold{= 11}

\boxed{\large\textsf{Possible answer \#1: \bf 11 }}\huge\checkmark

\huge\text{OR....}

\mathsf{\dfrac{(25-7)(2)}{4+2}}

\mathsf{25-7=\bf 18}

\mathsf{\dfrac{\bold{18}(2)}{4+2}}

\mathsf{18(2)=\bf 36}

\mathsf{\dfrac{\bold{36}}{4+2}}

\mathsf{4+2= \bf 6}

\mathsf{\dfrac{36}{\bold{6}}}

\mathsf{\bf = 6}

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\boxed{\boxed{\large\text{{Answer(s): \bf Answer \#1: 11 OR Answer \#2: 6}}}}\huge\checkmark

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3 0
3 years ago
Three airlines serve a small town in Ohio. Airline A has 48% of all scheduled flights, airline B has 26% and airline C has the r
kozerog [31]

Answer:

0.5969 = 59.69% probability that it was a flight of airline A

Step-by-step explanation:

Conditional Probability

We use the conditional probability formula to solve this question. It is

P(B|A) = \frac{P(A \cap B)}{P(A)}

In which

P(B|A) is the probability of event B happening, given that A happened.

P(A \cap B) is the probability of both A and B happening.

P(A) is the probability of A happening.

In this question:

Event A: Left on time.

Event B: From airline A.

Probability of a flight leaving on time:

81% of 48%(airline A).

61% of 26%(airline B)

40% of 26%(airline C). So

P(A) = 0.81*0.48 + 0.61*0.26 + 0.40*0.26 = 0.6514

Probability of leaving on time and being from airline A:

81% of 48%. So

P(A \cap B) = 0.81*0.48 = 0.3888

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P(B|A) = \frac{P(A \cap B)}{P(A)} = \frac{0.3888}{0.6514} = 0.5969

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3 years ago
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Answer:

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Step-by-step explanation:

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