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Mkey [24]
3 years ago
13

Complete the two-column proof using the answers in the bank. Given: V is the midpoint of (SU) ̅ .∠RSV ≅ ∠TUV Prove: ∆VUT ≅∆VSR

Mathematics
1 answer:
ivann1987 [24]3 years ago
8 0

Step-by-step explanation:

1.  V is the midpoint of  (SU) ̅    1.  Given

2. UV ≅ VS           2.  Definition of midpoint

3. ∠RSV ≅ ∠TUV            3. Given

4.  ∠SVR ≅∠UVT           4.  Vertical Angle Theorem

5.  ∆VUT ≅ ∆VSR          5.  ASA Congruence  


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4 years ago
The system of equations is graphed in the figure.
Scilla [17]

Answer:  The correct answer is:  [C]:

___________________________________________

              →    " ( 3, -2) " .

___________________________________________

Explanation:

___________________________________________

By looking at the graph {provided) of the lines of the 2 (two) equations given, we see that the two (2) lines intersect at the point at which the coordinates are:   " (3, -2)" ;  that is:  where:  " x = 3;  y = - 2 " ;  (refer to "image attached");

  →  which corresponds to:

 

  →  Answer choice:  [C]: " (3, -2) " .

___________________________________________

Let us check our answer, by plugging in "3" for "x" ; and "-2" for "y" ;

  in Each of the 2 (two) equations given; to see if the equations hold true:

_____________________________________

Equation 1:

_____________________________________

  y = (-5/3)x  + 3  ;

 →  -2  =? (-5/3)*3  + 3 ?  

 →  -2  =?  -5  + 3 ? ;    -2 =? -2 ?  Yes!

_____________________________________

Equation 2:

_____________________________________

 y = (1/3)x -3 ;

→  -2 =? (1/3)*3  - 3 ? ;

→  -2 =?  1 - 3 ?  ;    -2 = ? -2 ?  Yes!

_____________________________________

Both equations hold true when:  "x = 3 ;  and y = -2 " .

_____________________________________

Refer to image attached to see where the lines of the graphs of the equations given intersect.

_____________________________________

Hope this answer is helpful to you!

  WIshing you the best!

_____________________________________

3 0
3 years ago
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