Answer:
a) 13 m/s
b) (15 + h) m/s
c) 15 m/s
Step-by-step explanation:
if the location is
y=x²+3*x
then the average velocity from 3 to 7 is
Δy/Δx=[y(7)-y(3)]/(7-3)=[7²+3*7- (3²+3*3)]/4= 13 m/s
then the average velocity from x=6 to to x=6+h
Δy/Δx=[y(6+h)-y(6)]/(6+h-6)=[(6+h)²+3*(6+h)- (6²+3*6)]/h= (2*6*h+3*h+h²)/h=2*6+3= (15 + h) m/s
the instantaneous velocity can be found taking the limit of Δy/Δx when h→0. Then
when h→0 , limit Δy/Δx= (15 + h) m/s = 15 m/s
then v= 15 m/s
also can be found taking the derivative of y in x=6
v=dy/dx=2*x+3
for x=6
v=dy/dx=2*6+3 = 12+3=15 m/s
Answer:
100
Step-by-step explanation:
Solve for m
2m= 40
Divide both sides 2
m= 20
5(20)= 100
Area = πr². So you have the diameter which is 56 millimeters. And the radius (r) is half the diameter, so the radius would be 28 mm. Square 28 would be 784, multiplied by π would equal 2463.00864mm. Rounded to the nearest hundredth would be 2843.01mm².
12/3 = 4
4 cars per hour
4 x 5 = $20
20 x 8 = $160 for 8 hrs
