Question

What is an equation in slope-intercept form for the line that passes through the points (1 -3) and (3 1)

Answer 1

Answer:
$y = 2x - 5$

Explanation:

Slope-intercept form formula:
$y = mx + b$
For this formula we need the slope to find the slope use the slope formula:
$\frac{y_{2} - y}{x_{2} - x}$
Plug in the two points (1,-3) and (3,1)
$\frac{1 - - 3}{3 - 1}$
$\frac{4}{2}$
=2
the slope is 2

Now use the slope-interpect formula and plug in the slope (m)
$y = 2x + b$
plug in one point I'll use (3,1)
$1 = 2(3) + b$
1 = 6 +b
1-6=6-6+b
-5 = b

The equation would be:
$y = 2x - 5$