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Hitman42 [59]
3 years ago
12

Which expression is equivalent to the given expression?

Mathematics
2 answers:
vovikov84 [41]3 years ago
8 0
3(2a + 5) = 3 * 2a + 3 * 5 = 6a + 15
sergeinik [125]3 years ago
5 0
The answer is 6a + 15
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What is the answer please??
xenn [34]

Answer:

Answer is <em>n</em><em>/</em><em>2</em>

Step-by-step explanation:

I started with the constant n

In second step I divided the n by 2

answer \: is \:   \: \frac{n}{2}

<em>HAVE A NICE DAY</em><em>!</em>

<em>THANKS</em><em> </em><em>FOR GIVING ME THE OPPORTUNITY TO</em><em> </em><em>ANSWER YOUR QUESTION</em><em>. </em>

5 0
3 years ago
Read 2 more answers
The sum of the two angles of a triangle is 80 degree and their difference is 20 degree. find all the angles of the triangle.
Norma-Jean [14]

Sum of 2 angles = 80°

Difference = 20°

If we take away 20° from the sum, both angles are equal

⇒80 - 20 = 60°


Divide by 2 to find the smaller angle:

60 ÷ 2 = 30


Add 20° to find the bigger angle:

20 + 30 = 50°


<u>One of the angle is 30° and the other angle is 50°</u>


Given that the sum of the two angles is 80°

⇒ Third angle = 180 - 80 = 100°


Answer: The 3 angles are 30° , 50° and 100°

3 0
3 years ago
Read 2 more answers
Suppose small aircraft arrive at a certain airport according to a Poisson process with rate a 5 8 per hour, so that the number o
timurjin [86]

Answer:

(a) P (X = 6) = 0.12214, P (X ≥ 6) = 0.8088, P (X ≥ 10) = 0.2834.

(b) The expected value of the number of small aircraft that arrive during a 90-min period is 12 and standard deviation is 3.464.

(c) P (X ≥ 20) = 0.5298 and P (X ≤ 10) = 0.0108.

Step-by-step explanation:

Let the random variable <em>X</em> = number of aircraft arrive at a certain airport during 1-hour period.

The arrival rate is, <em>λ</em>t = 8 per hour.

(a)

For <em>t</em> = 1 the average number of aircraft arrival is:

\lambda t=8\times 1=8

The probability distribution of a Poisson distribution is:

P(X=x)=\frac{e^{-8}(8)^{x}}{x!}

Compute the value of P (X = 6) as follows:

P(X=6)=\frac{e^{-8}(8)^{6}}{6!}\\=\frac{0.00034\times262144}{720}\\ =0.12214

Thus, the probability that exactly 6 small aircraft arrive during a 1-hour period is 0.12214.

Compute the value of P (X ≥ 6) as follows:

P(X\geq 6)=1-P(X

Thus, the probability that at least 6 small aircraft arrive during a 1-hour period is 0.8088.

Compute the value of P (X ≥ 10) as follows:

P(X\geq 10)=1-P(X

Thus, the probability that at least 10 small aircraft arrive during a 1-hour period is 0.2834.

(b)

For <em>t</em> = 90 minutes = 1.5 hour, the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 1.5=12

The expected value of the number of small aircraft that arrive during a 90-min period is 12.

The standard deviation is:

SD=\sqrt{\lambda t}=\sqrt{12}=3.464

The standard deviation of the number of small aircraft that arrive during a 90-min period is 3.464.

(c)

For <em>t</em> = 2.5 the value of <em>λ</em>, the average number of aircraft arrival is:

\lambda t=8\times 2.5=20

Compute the value of P (X ≥ 20) as follows:

P(X\geq 20)=1-P(X

Thus, the probability that at least 20 small aircraft arrive during a 2.5-hour period is 0.5298.

Compute the value of P (X ≤ 10) as follows:

P(X\leq 10)=\sum\limits^{10}_{x=0}(\frac{e^{-20}(20)^{x}}{x!})\\=0.01081\\\approx0.0108

Thus, the probability that at most 10 small aircraft arrive during a 2.5-hour period is 0.0108.

8 0
3 years ago
What is an example of a number that is not real
kykrilka [37]
An example is the number 5i
7 0
3 years ago
Read 2 more answers
Evaluate: [5(2-6)+3(8÷4)^2]^2
ludmilkaskok [199]
The answer you're looking for will be,

ANSWER: 64.

Steps:
To get this answer, follow the PEMDAS order of operations.

PEMDAS: Parenthesis, Exponents, Multiply, Divide, Add, Subtract.
(IN ORDER IF POSSIBLE)

I hoped this helped, you're welcome :)
4 0
3 years ago
Read 2 more answers
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