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scoray [572]
3 years ago
14

Jim made 12,000 milliliter sod orange juice if he sells 1-liter bottles for $1.09 how much will he earn if he sells all of his b

ottles of juice
Mathematics
1 answer:
Natalija [7]3 years ago
8 0
So 12000 mil. litters is 12 liters

so multiply 12x1.09 and you get

$13.08

your answer is $13.08
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Vladimir says that the equation of the line that passes through points above Robyn says that the line passes through the points
aleksley [76]

Answer:

Both are correct

Step-by-step explanation:

The Line has the following equation: y= 1+4/5 x

So we need to know which points: (-5,-3) and (10,9), (-10,-7). (-15, -11) are part of the line

For instances, lest start by evaluating (-15,-11) in y=1+4/5 x

this leaves us to the following operation: -11=1+4/5 * (-15)

-11=1-4*3 resulting in a equality -11=-11, this point does belong to the line

Repeat the above for all of the remaining points and you will get the same conclusion, that is we Vladimir and Robyn are correct.

8 0
3 years ago
A grocery store charges $3.00 for 4 two-liter bottles of lemonade. David has $12.00 in his wallet. Since David is having a party
nevsk [136]
No because he will be $3.00 short.
So it is $0.75 a bottle. So then you multiply $0.75 by 20. You get $15.00
So David will not have enough in his wallet.
8 0
3 years ago
Write two linear expressions that have a sum of 3x-8
irakobra [83]
1. (5x + 2 )
2. ( -2x -10 ) 
5 0
3 years ago
Read 2 more answers
If you draw four cards at random from a standard deck of 52 cards, what is the probability that all 4 cards have distinct charac
mezya [45]

There are \binom{52}4 ways of drawing a 4-card hand, where

\dbinom nk = \dfrac{n!}{k!(n-k)!}

is the so-called binomial coefficient.

There are 13 different card values, of which we want the hand to represent 4 values, so there are \binom{13}4 ways of meeting this requirement.

For each card value, there are 4 choices of suit, of which we only pick 1, so there are \binom41 ways of picking a card of any given value. We draw 4 cards from the deck, so there are \binom41^4 possible hands in which each card has a different value.

Then there are \binom{13}4 \binom41^4 total hands in which all 4 cards have distinct values, and the probability of drawing such a hand is

\dfrac{\dbinom{13}4 \dbinom41^4}{\dbinom{52}4} = \boxed{\dfrac{2816}{4165}} \approx 0.6761

4 0
2 years ago
Help me you guys I will apprecaite
stepladder [879]
I think your answer would be 14 if this is what it’s asking for
Because 6/6 makes 1 so 13+1 is 14
6 0
3 years ago
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