Diameter = 40
Circumference is about 125.66
Area is about 1256.64
Answer:
Let
y=f(x)
so
y=log9x
we know that
applying property of logarithms
y= log9x is equal to
------> equation 1
so
case 1) (-1/81, 2)
x=-1/81
y=2
substitute the value of y in the equation 1 to obtain the value of x
81 is not equal to -1/81-------> the point does not belong to the graph
case 2) (0, 1)
x=0
y=1
substitute the value of y in the equation 1 to obtain the value of x
9 is not equal to 0-------> the point does not belong to the graph
case 3) (1/9, -1)
x=1/9
y=-1
substitute the value of y in the equation 1 to obtain the value of x
1/9 is equal to 1/9-------> the point belongs to the graph
case 4) (3, 243)
x=3
y=243
substitute the value of y in the equation 1 to obtain the value of x
9^{243} is not equal to 3-------> the point does not belong to the graph
case 5) (9, 1)
x=9
y=1
substitute the value of y in the equation 1 to obtain the value of x
9 is equal to 9-------> the point belongs to the graph
case 6) (81, 2)
x=81
y=2
substitute the value of y in the equation 1 to obtain the value of x
81 is equal to 81-------> the point belongs to the graph
Answer:
c
Step-by-step explanation:
Something funny is that the x value of the vertex lies directl in the middle of the x intercepts
so
we see the x intercepts or 0's at x=8 and 2
the average is x=5
so find f(5) to find the y value of the vertex
f(5)=(5-8)(5-2)
f(5)=(-3)(3)
f(5)=-9
vertex is at (5,-9)
the actual way the teacher wants is to expand then compltete the square to get into the form f(x)=a(x-h)^2+k where the vertex is (h,k)
but whatever
verrtex is at (5,-9)