Ask question

Ask question

All categories

3 years ago

6

What’s the complement for 12 degrees

1 answer:

Andre45 [30]3 years ago

6 0

The complementary angle of 12 degrees, is 78 degrees.

Complementary angles are angles that when added together have an end result of 90 degrees. So, to find the answer, simply subtract 12 from 90. Thus making the answer 78 degrees.

I hope this helps!

You might be interested in

Find the value of sin 0<br>cos(90°- 0) + cos 0 sin(90°-0)

Step2247 [10]

Step-by-step explanation:

$sin \theta \: cos(90 \degree - \theta) + cos \theta \: sin(90 \degree - \theta) \\ = sin(\theta + 90 \degree - \theta) \\ = sin(90 \degree) \\ = 1$

5 0

4 years ago

Which is the simplified form of the expression (6 Superscript negative 2 Baseline times 6 Superscript 5 Baseline) Superscript ne

Finger [1]

Answer: The answer is B

8 0

3 years ago

Read 2 more answers

Writing Algebraic Expressions the product of 3 and X

Vlada [557]

Step-by-step explanation:

$3 \times x$

$3x$

7 0

2 years ago

Find all of the equilibrium solutions. Enter your answer as a list of ordered pairs (R,W), where R is the number of rabbits and

zloy xaker [14]

Answer:

$(0,0)$ $(4000,0)$ and $(500,79)$

Step-by-step explanation:

Given

See attachment for complete question

Required

Determine the equilibrium solutions

We have:

$\frac{dR}{dt} = 0.09R(1 - 0.00025R) - 0.001RW$

$\frac{dW}{dt} = -0.02W + 0.00004RW$

To solve this, we first equate $\frac{dR}{dt}$ and $\frac{dW}{dt}$ to 0.

So, we have:

$0.09R(1 - 0.00025R) - 0.001RW = 0$

$-0.02W + 0.00004RW = 0$

Factor out R in $0.09R(1 - 0.00025R) - 0.001RW = 0$

$R(0.09(1 - 0.00025R) - 0.001W) = 0$

Split

$R = 0$ or $0.09(1 - 0.00025R) - 0.001W = 0$

$R = 0$ or $0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

Factor out W in $-0.02W + 0.00004RW = 0$

$W(-0.02 + 0.00004R) = 0$

Split

$W = 0$ or $-0.02 + 0.00004R = 0$

Solve for R

$-0.02 + 0.00004R = 0$

$0.00004R = 0.02$

Make R the subject

$R = \frac{0.02}{0.00004}$

$R = 500$

When $R = 500$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 -2.25 * 10^{-5} * 500 - 0.001W = 0$

$0.09 -0.01125 - 0.001W = 0$

$0.07875 - 0.001W = 0$

Collect like terms

$- 0.001W = -0.07875$

Solve for W

$W = \frac{-0.07875}{ - 0.001}$

$W = 78.75$

$W \approx 79$

$(R,W) \to (500,79)$

When $W = 0$ , we have:

$0.09 - 2.25 * 10^{-5}R - 0.001W = 0$

$0.09 - 2.25 * 10^{-5}R - 0.001*0 = 0$

$0.09 - 2.25 * 10^{-5}R = 0$

Collect like terms

$- 2.25 * 10^{-5}R = -0.09$

Solve for R

$R = \frac{-0.09}{- 2.25 * 10^{-5}}$

$R = 4000$

So, we have:

$(R,W) \to (4000,0)$

When $R =0$ , we have:

$-0.02W + 0.00004RW = 0$

$-0.02W + 0.00004W*0 = 0$

$-0.02W + 0 = 0$

$-0.02W = 0$

$W=0$

So, we have:

$(R,W) \to (0,0)$

Hence, the points of equilibrium are:

$(0,0)$ $(4000,0)$ and $(500,79)$

4 0

3 years ago

Find the value of <br><img src="https://tex.z-dn.net/?f=%20log_%7B8%7D%5E%7B512%7D%20" id="TexFormula1" title=" log_{8}^{512} "

valina [46]

Answer: 3
Explanation: logarithm base 8 of 512 is 3

8 0

3 years ago