This is an exponential equation. We will solve in the following way. I do not have special symbols, functions and factors, so I work in this way
2 on (2x) - 5 2 on x + 4=0 =>. (2 on x)2 - 5 2 on x + 4=0 We will replace expression ( 2 on x) with variable t => 2 on x=t =. t2-5t+4=0 => This is quadratic equation and I solve this in the folowing way => t2-4t-t+4=0 => t(t-4) - (t-4)=0 => (t-4) (t-1)=0 => we conclude t-4=0 or t-1=0 => t'=4 and t"=1 now we will return t' => 2 on x' = 4 => 2 on x' = 2 on 2 => x'=2 we do the same with t" => 2 on x" = 1 => 2 on x' = 2 on 0 => x" = 0 ( we know that every number on 0 gives 1). Check 1: 2 on (2*2)-5*2 on 2 +4=0 => 2 on 4 - 5 * 4+4=0 => 16-20+4=0 =. 0=0 Identity proving solution.
Check 2: 2 on (2*0) - 5* 2 on 0 + 4=0 => 2 on 0 - 5 * 1 + 4=0 =>
1-5+4=0 => 0=0 Identity provin solution.
5x’2-4x+7-4x-2
We add the two 4
5x’2-8x+7-2
5x’2-8x+5
The answer is
5x’2 -8x +5
60 Student
5/7=0.71428571428<span>
</span>60/84=0.71428571428
7/15, 0.65, .0715
7/15 = .467
Hope this helps you! (:
-PsychoChicken4040
50x+80y=1750 and y = x+4 can be used to determine the number of small boxes and large boxes of paper shipped where x represent the number of small boxes of paper and y represent the number of large boxes of paper.
Step-by-step explanation:
Given,
Weight of small box of paper = 50 pounds
Weight of large box of paper = 80 pounds
Total weight of boxes = 1750 pounds
Let,
x represent the number of small boxes of papers.
y represent the number of large boxes of papers.
According to given statement;
50x+80y=1750
y = x+4
50x+80y=1750 and y = x+4 can be used to determine the number of small boxes and large boxes of paper shipped where x represent the number of small boxes of paper and y represent the number of large boxes of paper.
Keywords: linear equation, addition
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