Charles is doing renovations on his house. He has budgeted 25% of the cost for new

julia, keller and israel all made 219.75 dollars in total. keller made 37.50 and israel made 12 less than keller. what did each

krek1111 [17]

Keller=37.50
Israel=25.50
Julia=194.25

8 0

3 years ago

Write the equation g(x) in vertex form of a

DerKrebs [107]

The equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1

Given a quadratic function for the transformations given the function f(x) = x²

If the function g(x) of the graph is translated 4 units to the left, the equation becomes (x-4)² (note that we subtracted 4 from the x value

Translating the graph 1 unit up will give the final function g(x) as (x-4)² + 1 (We added 1 since it is an upward translation.)

Hence the equation g(x) in vertex form of a quadratic function for the transformations whose graph is a translation 4 units left and 1 unit up of the graph of f(x) is (x-4)² + 1

Learn more here: brainly.com/question/15381183

8 0

2 years ago

Gibbs Baby Food Company wishes to compare the weight gain of infants using its brand versus its competitor’s. A sample of 40 bab

Leviafan [203]

Answer:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

Step-by-step explanation:

Information given

$\bar X_{1}=7.6$ represent the mean for Gibbs products

$\bar X_{2}=8.1$ represent the mean for the competitor

$\sigma_{1}=2.3$ represent the population standard deviation for Gibbs

$\sigma_{2}=2.9$ represent the sample standard deviation for the competitor

$n_{1}=40$ sample size for the group Gibbs

$n_{2}=55$ sample size for the group competitor

$\alpha=0.05$ Significance level provided

z would represent the statistic

Hypothesis to verify

We want to check if babies using the Gibbs brand gained less weight, the system of hypothesis would be:

Null hypothesis: $\mu_{1}-\mu_{2}=0$

Alternative hypothesis: $\mu_{1} - \mu_{2}< 0$

The statistic would be given by:

$z=\frac{(\bar X_{1}-\bar X_{2})-\Delta}{\sqrt{\frac{\sigma^2_{1}}{n_{1}}+\frac{\sigma^2_{2}}{n_{2}}}}$ (1)

Replacing the info given we got:

$z=\frac{(7.6-8.1)-0}{\sqrt{\frac{2.3^2}{40}+\frac{2.9^2}{55}}}}=-0.936$

The p value can be founded with this formula:

$p_v =P(z$

Since the p value is higher than the significance level provided of 0.05 we have enough evidence to FAIL to reject the null hypothesis and we can't conclude that the true mean for the Gibbs brand is significantly lower than the true mean for the competitor

5 0

3 years ago

Which of the following are identities? Check all that apply. A. cot2x + 1 = csc2x B. tan2x = 1 - sec2x C. sin2x = 1 + cos2x D. s

kirill115 [55]

I'll assume those are squares. We know D is an identity:

$\sin^2 x + \cos ^2 x = 1$

Dividing through by $\sin ^2 x$

$1 + \cot^2 x = \csc^2 x$

That's A.

Dividing the original through by $\cos ^2 x$

$\tan^2 x + 1 = \sec^2 x$

Not quite B, wrong sign on tangent.

C has the wrong sign on cosine squared as well.

Identities: A & D

4 0

3 years ago

You are dividing 30 tomato plants into equal rows for planting. how many possibilities are there?

Ierofanga [76]

Answer:

6,5 5,6 3,10 10,3 1,30 30,1 2,15 15,2 = 8 possibilities

Step-by-step explanation:

8 0

3 years ago

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