Answer:
c = 1/32
Step-by-step explanation:
32-x-x-x-x-x-x-x
32/4 = 8
so product 1/4 is the rule
32/4^5= 2^5/2^10
2^-5=1/32
Answer:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Step-by-step explanation:
For this case first we need to create the sample of size 20 for the following distribution:

And we can use the following code: rnorm(20,50,6) and we got this output:
> a<-rnorm(20,50,6)
> a
[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905
[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501
Then we can find the mean and the standard deviation with the following formulas:
> mean(a)
[1] 50.72451
> sqrt(var(a))
[1] 7.470221
Answer:
D={3,9}
The numbers are 3 and 9
Step-by-step explanation:
The set A
={,,,,,,,,,}
Let B be the sub set of A containing odd numbers
B={1,3,5,7,9}
Let C be the sub set of A containing multiply of 3
C= {3,6,9}
Now let D be the be the sub set of A containing both odd numbers and multiples of 3
D={3,9}