X^2-7x-4=0
(x-7/2)^2-(7/2)^2-4=0
(x-7/2)^2-(7)^2/(2)^2-4=0
(x-7/2)^2-49/4-4=0
(x-7/2)^2+(-49-4*4)/4=0
(x-7/2)^2+(-49-16)/4=0
(x-7/2)^2+(-65)/4=0
(x-7/2)^2-65/4=0
(x-7/2)^2-65/4+65/4=0+65/4
(x-7/2)^2=65/4
sqrt[ (x-7/2)^2 ]=+-sqrt(65/4)
x-7/2=+-sqrt(65)/sqrt(4)
x-7/2=+-sqrt(65)/2
x-7/2+7/2=+-sqrt(65)/2+7/2
x=7/2+-sqrt(65)/2
x=[7+-sqrt(65)]/2
x1=[7-sqrt(65)]/2
x2=[7+sqrt(65)]/2
Answer:
Circumference of circle = (15.5)π cm
Step-by-step explanation:
Missing information:
Area of circle = 60π cm²
Find:
Circumference of circle
Computation:
Area of circle = πr²
Area of given circle = π(Radius of circle)²
60π = πr²
60 = r²
Radius of circle = 7.75 cm (Approx)
Circumference of circle = 2πr
Circumference of circle = 2(π)(7.75)
Circumference of circle = (15.5)π cm
558 gallons are used when the car has been driven 18 miles.
<u>Step-by-step explanation:</u>
<u>From the given data, it can be determined that :</u>
- The number of gallons for 2 miles = 62 gallons
- The number of gallons for 4 miles = 124 gallons
- The number of gallons for 10 miles = 310 gallons
Let, the number of gallons for 18 miles = 'x' gallons
<u>To find x :</u>
compare the given data with the unknown data,
62 gallons / 2 miles = x gallons / 18 miles
keep x alone on one side,
x = (62×18) / 2
x = 31×18
x = 558 gallons
Therefore, 558 gallons are used to drive 18 miles.
The answer is C
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Answer:
Volume of the empty space in the can is 327.05 
Step-by-step explanation:
Given:
Number of golf ball the can holds = 4
Diameter of the golf ball = 5 cm
To Find:
Volume of the empty space in the can = ?
Solution:
Step 1: Finding the volume of one golf ball
Ball is shape of the sphere
So lets use the volume of the sphere formula
Volume of the golf ball = 
Radius =
= 2.5 cm
Substituting the values
Volume of the golf ball
=
=
= 
= 
= 65.41
Step 2: Finding the volume of empty space of the can
volume of empty space of the can = volume of 5 golf ball
= 5 X 65.41
= 327.05