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Alinara [238K]
3 years ago
13

Please help!! thank you

Mathematics
1 answer:
uysha [10]3 years ago
6 0

Answer: It would be E

Step-by-step explanation:

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Vsevolod [243]

Answer:

is there a picture

Step-by-step explanation:

4 0
3 years ago
Use the fundamental identities and appropriate algebraic operations to simplify the following expression. (18 +tan x) (18-tan x)
andrezito [222]

Answer:

a) \left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right)=325

b) The lowest point of y=\cos \left(x\right), 0\leq x\leq 2\pi is when x = \pi

Step-by-step explanation:

a) To simplify the expression \left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)+\sec ^2\left(x\right) you must:

Apply Difference of Two Squares Formula: \left(a+b\right)\left(a-b\right)=a^2-b^2

a=18,\:b=\tan \left(x\right)

\left(18+\tan \left(x\right)\right)\left(18-\tan \left(x\right)\right)=18^2-\tan ^2\left(x\right)=324-\tan ^2\left(x\right)

324-\tan ^2\left(x\right)+\sec ^2\left(x\right)

Apply the Pythagorean Identity 1+\tan ^2\left(x\right)=\sec ^2\left(x\right)

From the Pythagorean Identity, we know that 1=-\tan ^2\left(x\right)+\sec ^2\left(x\right)

Therefore,

324[-\tan ^2\left(x\right)+\sec ^2\left(x\right))]\\324[+1]\\325

b) According with the below graph, the lowest point of y=\cos \left(x\right), 0\leq x\leq 2\pi is when x = \pi

3 0
3 years ago
37 is ____ % of 148; 148 is ____ % of 37
pashok25 [27]

Answer:

25% ; 400%

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Can you please help me
max2010maxim [7]
Here’s the answer and each step I took to solve it. With the example I made on the side just continue to repeat that for each one to get the answers. You just replace that one number for the X to take the place for the next X value as you go down the table solving them.

7 0
3 years ago
Find a vector function, r(t), that represents the curve of intersection of the two surfaces. the paraboloid z = 9x2 y2 and the p
dolphi86 [110]

The vector function is, r(t) =  \bold{ < t,2t^2,9t^2+4t^4 > }

Given two surfaces for which the vector function corresponding to the intersection of the two need to be found.

First surface is the paraboloid, z=9x^2+y^2

Second equation is of the parabolic cylinder, y=2x^2

Now to find the intersection of these surfaces, we change these equations into its parametrical representations.

Let x = t

Then, from the equation of parabolic cylinder,  y=2t^2.

Now substituting x and y into the equation of the paraboloid, we get,

z=9t^2+(2t^2)^2 = 9t^2+4t^4

Now the vector function, r(t) = <x, y, z>

So r(t) = \bold{ < t,2t^2,9t^2+4t^4 > }

Learn more about vector functions at brainly.com/question/28479805

#SPJ4

7 0
2 years ago
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