What happens to a low-frequency photon when it hits a metal plate if its energy is less than the work function W0?
2 answers:
Answer:
There is no emission of electron
Explanation:
As we know by Einstein equation
now if the initial frequency of photon is very small or if it is less than the work function of the metal then in that case the photon energy is not sufficient to eject out an electron from metal.
So here the photon is not absorbed by the metal and reflected back by the surface. So photoelectric emission is only possible when the incident photon is having energy more than the energy of the work function.
So here we can say that there is no emission of electron from that surface
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The related concept to solve this exercise is given in the expressions that the magnetic field has both as a function of the number of loops, current and length, as well as inductance and permeability. The first expression could be given as,
The magnetic field H is given as,
Here,
n = Number of turns of the coil
I = Current that flows in the coil
l = Length of the coil
From the above equation, the number of turns of the coil is,
The magnetic field is again given by,
Where the minimum inductance produced by the solenoid coil is B.
We have to obtain n, that
Replacing with our values we have that,
Therefore the number of turn required is 28Truns