1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Studentka2010 [4]
3 years ago
15

the density of atmosphere (measured in kilograms/meter3) on a certain planet is found to decrease as altitude increases (as meas

ured from the planet's surface). what type of relationship exists between the altitude and the atmospheric density, and what would the atmospheric density be at an altitude of 1,291 kilometers?
Physics
2 answers:
vladimir1956 [14]3 years ago
6 0

Answer

As the density of atmosphere (measured in kilograms/meter3) on a certain planet is found to decrease as altitude increases (as measured from the planet's surface). Therefore inverse relationship exists between the altitude and the atmospheric density,

we know that

on planet earth, when height is less than 36512km we use following formula to determine the density

density= pressure/(1718\times(59-.00365height+459.7)

therefore density at height=1,291 kilometers is given as

[tex]density=\frac{pressure}{(1718\times(59-(.00365\times 1291)+459.7)}\\ density=\frac{pressure}{(1718\times(59-4.71+459.7)}\\density=\frac{pressire}{883031.1263}[/tex]

statuscvo [17]3 years ago
5 0
The type of relationship between atmospheric density and altitude is therefore inverse relationship. This means an increase in either will decrease the other factor. Density is mass per unit volume, it is difficult to calculate with only altitude 1,291 kilometers given. Else, we could also use temperature and pressure to solve density but they are not provided.
You might be interested in
What is the potential difference across a parallel-plate capacitor whose plates are separated by a distance of 4.0 mm where each
suter [353]

The potential difference across the parallel plate capacitor is 2.26 millivolts

<h3>Capacitance of a parallel plate capacitor</h3>

The capacitance of the parallel plate capacitor is given by C = ε₀A/d where

  • ε₀ = permittivity of free space = 8.854 × 10⁻¹² F/m,
  • A = area of plates and
  • d = distance between plates = 4.0 mm = 4.0 × 10⁻³ m.

<h3>Charge on plates</h3>

Also, the surface charge on the capacitor Q = σA where

  • σ = charge density = 5.0 pC/m² = 5.0 × 10⁻¹² C/m² and
  • a = area of plates.

<h3>The potential difference across the parallel plate capacitor</h3>

The potential difference across the parallel plate capacitor is V = Q/C

= σA ÷ ε₀A/d

= σd/ε₀

Substituting the values of the variables into the equation, we have

V = σd/ε₀

V = 5.0 × 10⁻¹² C/m² × 4.0 × 10⁻³ m/8.854 × 10⁻¹² F/m

V = 20.0 C/m × 10⁻³/8.854 F/m

V = 2.26 × 10⁻³ Volts

V = 2.26 millivolts

So, the potential difference across the parallel plate capacitor is 2.26 millivolts

Learn more about potential difference across parallel plate capacitor here:

brainly.com/question/12993474

7 0
3 years ago
Help me please and thank you
katovenus [111]

Answer:

go to : www.planetresourses.com/test2.00/answers, ant type in that test name

Explanation:

yee

3 0
3 years ago
Suppose that, from measurements in a microscope, you determine that a certain bacterium covers an area of 1.50 μm2. Convert this
Paladinen [302]
1 m = 1 000 000 ym

converted other way we can say that:

1 ym = 10^{-6} m

Now, since we have ym^2 which is ym*ym which means:
1 ym^2 = (10^{-6}) ^2  =  10^{-12} m

we have 1,5 ym^2 which means that answer is:
1.5* 10^{-12} m
8 0
4 years ago
50g of ice at 0°C is mixed with 50g of water at 80°C, what will be the final temperature of a mixture in
xxTIMURxx [149]

Answer:

0° C

Explanation:

Given that

Mass of ice, m = 50g

Mass of water, m(w) = 50g

Temperature of ice, T(i) = 0° C

Temperature of water, T(w) = 80° C

Also, it is known that

Specific heat of water, c = 1 cal/g/°C

Latent heat of ice, L(w) = 89 cal/g

Let us assume T to be the final temperature of mixture.

This makes the energy balance equation:

Heat gained by ice to change itself into water + heat gained by melted ice(water) to raise its temperature at T° C = heat lost by water to reach at T° C

m(i).L(i) + m(i).c(w)[T - 0] = m(w).c(w)[80 - T], on substituting, we have

50 * 80 + 50 * 1(T - 0) = 50 * 1(80 - T)

4000 + 50T = 4000 - 50T

0 = 100 T

T = 0° C

Thus, the final temperature is 0° C

3 0
3 years ago
Properties of light that define light as a wave?
MAVERICK [17]
The first choices are correct, because the second choices could happen by things other than light.
6 0
3 years ago
Read 2 more answers
Other questions:
  • L
    12·1 answer
  • What are some ways that electric fields are similar to magnetic fields?
    12·1 answer
  • Explain the process that causes dew to form on blades of grass. ​
    8·2 answers
  • How much heat is needed to change the temperature of 3 grams of gold (c = 0.129 ) from 21°C to 363°C? The answer is expressed to
    11·2 answers
  • A 5.00 g object moving to the right at 20.0 cm/s makes an elastic head-on collision with a 10.0 g object that is initially at re
    10·1 answer
  • The Force of friction between an object and the surface upon which it is sliding is 12N. The weight of the object is 20N. What i
    12·1 answer
  • A hydraulic press must exert a force of 20,000N to crush a wrecked car into a convienent block. If the output piston is eight ti
    6·1 answer
  • The mass of the hammer is 0.454 kg. Calculate the weight of the hammer.
    9·2 answers
  • A glass of root beer with a scoop of ice cream floating on top and a straw sticking out.
    7·1 answer
  • Tamsin strikes a golf ball so that it flies off with a speed of 60 m/s. The golf ball has a mass of 45 g. Calculate the kinetic
    11·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!