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Studentka2010 [4]
3 years ago
15

the density of atmosphere (measured in kilograms/meter3) on a certain planet is found to decrease as altitude increases (as meas

ured from the planet's surface). what type of relationship exists between the altitude and the atmospheric density, and what would the atmospheric density be at an altitude of 1,291 kilometers?
Physics
2 answers:
vladimir1956 [14]3 years ago
6 0

Answer

As the density of atmosphere (measured in kilograms/meter3) on a certain planet is found to decrease as altitude increases (as measured from the planet's surface). Therefore inverse relationship exists between the altitude and the atmospheric density,

we know that

on planet earth, when height is less than 36512km we use following formula to determine the density

density= pressure/(1718\times(59-.00365height+459.7)

therefore density at height=1,291 kilometers is given as

[tex]density=\frac{pressure}{(1718\times(59-(.00365\times 1291)+459.7)}\\ density=\frac{pressure}{(1718\times(59-4.71+459.7)}\\density=\frac{pressire}{883031.1263}[/tex]

statuscvo [17]3 years ago
5 0
The type of relationship between atmospheric density and altitude is therefore inverse relationship. This means an increase in either will decrease the other factor. Density is mass per unit volume, it is difficult to calculate with only altitude 1,291 kilometers given. Else, we could also use temperature and pressure to solve density but they are not provided.
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Answer:

g=274\ m/s^2

Explanation:

Mass of the Sun, M=1.99\times 10^{30}\ kg

The radius of the Sun, r=6.96\times 10^8\ m

We need to find the acceleration due to gravity on the surface of the Sun. It is given by the formula as follows :

g=\dfrac{GM}{r^2}\\\\g=\dfrac{6.67\times 10^{-11}\times 1.99\times 10^{30}}{(6.96\times 10^8)^2}\\\\g=274\ m/s^2

So, the value of acceleration due to gravity on the Sun is 274\ m/s^2.

8 0
3 years ago
Which statement is accurate about how the aurora borealis is formed?
g100num [7]

Answer:

When the electrons jump to a higher energy state, they release energy as electromagnetic radiation, light.

Explanation:

When the solar wind gets past the magnetic field and travels towards the Earth, it runs into the atmosphere. As the protons and electrons from the solar wind hit the particles in the Earth's atmosphere, they release energy – and this is what causes the northern lights.

7 0
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A lamp draws a current of 0.50 A when it is connected to a 120 V source? What is the resistance of the lamp?
emmainna [20.7K]
Given,
Current (I) = 0.50A
Voltage (V) = 120 volts
Resistance (R) =?
We know that:-
Voltage (V) = Current (I) x Resistance (R)
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8 0
3 years ago
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What is represented by the slope of this graph
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A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0
otez555 [7]

The given question is incomplete. The complete question is as follows.

A box of oranges which weighs 83 N is being pushed across a horizontal floor. As it moves, it is slowing at a constant rate of 0.90 m/s each second. The push force has a horizontal component of 20 N and a vertical component of 25 N downward. Calculate the coefficient of kinetic friction between the box and the floor.

Explanation:

The given data is as follows.

    F_{1} = 20 N, F_{2} = 25 N, a = -0.9 m/s^{2}

             W = 83 N

         m = \frac{83}{9.81}

             = 8.46

Now, we will balance the forces along the y-component as follows.

       N = W + F_{2}

           = 83 + 25 = 108 N

Now, balancing the forces along the x component as follows.

       F_{1} - F_{r} = ma

        20 - F_{r} = 8.46 \times (-0.9)

             F_{r} = 7.614 N

Also, we know that relation between force and coefficient of friction is as follows.

             F_{r} = \mu \times N

          \mu = \frac{F_{r}}{N}

                    = \frac{7.614}{108}

                    = 0.0705

Thus, we can conclude that the coefficient of kinetic friction between the box and the floor is 0.0705.

7 0
4 years ago
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