1. Find the cost of levelling the ground in the form of a triangle having the sides 51 m, 37 m and 20 m at the rate of ₹ 3 per m².
a = 51 m, b = 37 m, c = 20 m
semiperimeter: p = (51+37+20):2 = 54 m
Area of triangle:

Rate: ₹ 3 per m².
Cost: ₹ 3•306 = ₹ 918
2. Find the area of the isosceles triangle whose perimeter is 11 cm and the base is 5 cm.
a = 5 cm
a+2b = 11 cm ⇒ 2b = 6 cm ⇒ b = 3 cm
p = 11:2 = 5.5

3. Find the area of the equilateral triangle whose each side is 8 cm.
a = b = c = 8 cm
p = (8•3):2 = 12 cm

4. The perimeter of an isosceles triangle is 32 cm. The ratio of the equal side to its base is 3 : 2. Find the area of the triangle.
a = 2x
b = 3x
2x + 2•3x = 32 cm ⇒ 8x = 32 cm ⇒ x = 4 cm ⇒ a = 8 cm, b = 12 cm
p = 32:2 = 16 cm

Answer:
9+x = 2y+14
Step-by-step explanation:
It says 9 plus a number, so plug in x for 'a number', and it says 'is twice a number plus 14'. Plug in '=' for is another variable for 'a number', and last but not least, just put +14 for plus 14
Answer:
h(x)=x²+6 and g(x)=8x-5
prove that hg(x)=19
Step-by-step explanation:
step 1: hog(x)=h[g(x)]
step 2: h(8x-5)
step 3: h(8x-5)= (8x-5)²+6
step 4: (8x-5)(8x-5)+6
step 5: 16x² +15x +6
Answer:

Step-by-step explanation:

factorise 216

since it is square root (meaning it has index to) pair up the number


Answer:
<u>The answer is -4 3/5</u>
Step-by-step explanation:
Let's reduce to its simplest form:
-3/5 + (-8/2) =
Step 1: Lowest Common Denominator (10):
- 6/10 + (-40/10) =
Step 2: Solve the parentheses:
- 6/10 - 40/10 =
Step 3: Subtract the fractions:
-46/10
Step 4: Simplify (Dividing by 2):
-23/5
Step 5: Converting the fraction to mixed number:
-4 3/5
<u>The answer is -4 3/5</u>