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Anon25 [30]
3 years ago
13

Classical conditioning requires _____. the pairing of two stimuli chaining small actions to make one big action a dog and a bell

none of the options
Social Studies
1 answer:
vampirchik [111]3 years ago
3 0
A classical conditioning definitely demands a pairing of two stimuli this is the correct answer! The classical conditioning is a learning mechanism that associates the two.

It was discovered on a dog and using a bell, but this was just one example, so a dog and a bell are not necessary in all cases:)
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Why did puritans start a colony separate from the pilgrims
Marrrta [24]

Answer: The Pilgrims and Puritans came to America to practice religious freedom. In the 1500s England broke away from the Roman Catholic Church and created a new church called the Church of England. Everyone in England had to belong to the church. ... The Pilgrims decided to settle in this area and called it Plymouth.

Hope this helps!!! Good luck!!! ;)

8 0
3 years ago
Emotions often run high when negative messages are involved for both the sender and the receiver which makes high standards of e
Lubov Fominskaja [6]

Answer:

A. True

Explanation:

When emotions run high there is the high tendency for individuals to use and utter negative messages and words . This could happen for both the sender and the receiver.

Having a high standards of ethics and etiquette involves having a polite and professional behavior ensures such utterances or actions are kept in checked and controlled.

8 0
3 years ago
A historian would find this poem most useful to understand
RoseWind [281]
D!


Have an amazing day!
8 0
3 years ago
Read 2 more answers
The Old San Antonio Road stretched from Louisiana, through Texas, and into __________.
stira [4]
D . The Gulf of Mexico is the answer .
7 0
3 years ago
Read 2 more answers
Question 9 please both a and b
GarryVolchara [31]

a^k - b^k = (a - b)(a^{k-1} + a^{k-2}b + ... + b^{k-1})

a. Let's set a=3, b=1

3^k - 1^k = (3 - 1)(\textrm{some integer we'll call } m)

3^k = 1 + 2m

In other words 3^k is odd, i.e. 3^k has remainder 1 when divided by 2. \quad\checkmark

b. Let

k=2n, a=3, b=1

a^k - b^k = (a - b)(a^{k-1} + a^{k-2}b + ... + b^{k-1})

3^{2n} - 1^{2n} = (3 - 1 )(3^{2n-1} + 3^{2n-2} + ... + 1)

There are 2n terms in the last factor.  All the terms of the form

3^{2n-k}

are odd. So when we add up an even number of them, we get an even number, call it 2m.

3^{2n} - 1 = 2(2m)

3^{2n} - 1 = 4m

We've shown 3^{2n}-1 is divisible by four.  \quad \checkmark

Merry Christmas!

3 0
3 years ago
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