h=9
A=((a+b)/2)h
234=((32+20)/2)h
234=(52/2)h
234=26h
9=h
Answer:
<em>Riko is wrong because she uses the wrong formula.</em>
Step-by-step explanation:
Given the coordinate points (-2, -3) and (2, -5)
We are to find the distance between the two points
Using the formula:
D = √(x2-x1)²+(y2-y1)²
From the coordinates x1 = -2, y1 = -3, x2 = 2 and y2 = -5
Substitute
D = √(2-(-2))²+(-5-(-3))²
D= √(4)²+(-2)²
D = √16 + 4
D = √20
D = √4*√5
D = 2√5
<em>This shows that Riko is wrong because she uses the wrong formula.</em>
Answer:
There are many. Two examples are

Step-by-step explanation:
There are many examples. The simplest is
1 -

It is trivial that

2 -

That function is injective as well.

An example of a function that is NOT injective is

Notice that

(-2,2)(2,-2)
slope = (-2 - 2) / (2 - (-2) = -4/4 = -1
as far as point slope form, there can be 2 answers...
y - y1 = m(x - x1)
slope(m) = -1
using points (-2,2)...x1 = -2 and y1 = 2
now we sub
y - 2 = -1(x - (-2) =
y - 2 = -1(x + 2) <== or could be written as y - 2 = - (x + 2)
y - y1 = m(x - x1)
slope(m) = -1
using points (2,-2)...x1 = 2 and y1 = -2
now we sub
y - (-2) = -1(x - 2) =
y + 2 = -1(x - 2) <== or can be written as y + 2 = - (x - 2)
either one of those answers is ur point slope form
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