Answer:
I'm not fully sure if this will work, however, I'm 92% sure it is correct.
Explanation:
startingrange = int(input("Enter a number for the starting of the range: "))
endingrange = int(input("Enter a number for the ending of the range: "))
divisiblebythree = 0
divisiblebyfive = 0
even = 0
odd = 0
for i in range(startingrange, endingrange):
if (i % 2) == 0:
even += 1
elif (i % 2) != 0:
odd += 1
if (i % 3) == 0:
divisiblebythree+=1
if (i%5) == 0:
divisiblebyfive+=1
print("Numbers divisible by 5:",divisiblebyfive)
print("Numbers divisible by 3:",divisiblebythree)
print("Odd numbers:",odd)
print("Even numbers:",even)
Answer:
best-fit
Explanation:
Best-fit: Closest in size to the request: In the Dynamic Partitioning technique of memory management, the placement algorithm that scans memory from the location of the last placement and chooses the next available block that is large enough to satisfy the request
Explanation:
11. True
12: Electronic Fund Transfer
13. True
14. I'm not sure but I think yes?..
(I'm not sure if your including number 15 but just in case, the full form of PIN is personal identification number)
Person A, of course. This person is the original maker of the image therefore that person has the rights to that image, person B does not automatically become the owner just by using it on his website. So the answer is person A.
Pecting Java<span> 2's </span>stack inspection<span> policy to be enforced can-. not execute on .... Figure 2. PSLang security policy that </span>allows<span> at most 10 open windows. .... </span>Method<span> call/return: A → B. At start of B, look up</span>protection<span> domain PB for B's. code and push PB on the thread-local domain-. </span>Stack<span>. At return from B (either normally or by.</span>
