2 years ago

Solve this system of linear equations. Separate

Mathematics

1 answer:

Katyanochek1 [597]2 years ago

5 0

Answer:

good question

Step-by-step explanation:

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HURRYYYYY<br> What is the value of the expression 4’4?

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Answer:

256

Step-by-step explanation:

Raise 4 to the power of 4

Basically, multiply 4 by itself four times. :)

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2 years ago

The sequences below are either arithmetic sequences or geometric sequences. For each sequence, determine whether it is arithmeti

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a) Arithmetic yₙ = 3*(n - 1) + 13

b) Geometric yₙ = 2*5⁽ⁿ⁻¹⁾

Step-by-step explanation:

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2 years ago

Order the numbers from least to greatest.<br><br> −34, 0.5, 23,−73, 1.2

dybincka [34]

Answer:

0.5,1.2,23,-34,-73

Step-by-step explanation:

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3 years ago

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Vani bought two pounds of strawberries for $8.00. What is the price, in dollars per ounce of strawberries?

WARRIOR [948]

Answer:

the prize is 8.00 for 1 pound

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2 years ago

Find the Taylor series for f(x) centered at the given value of a. [Assume that f has a power series expansion. Do not show that

kherson [118]

Answer:

The answer is

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

Step-by-step explanation:

Remember that Taylor says that

$f(x) = {\displaystyle \sum\limits_{k=0}^{\infty} \frac{f^{(k)}(a) }{k!}(x-a)^k }$

For this case

$f^{(0)} (-2) = 8(-2)-3(-2)^3 = 8\\f^{(1)} (-2) = 8-3(3)(-2)^2 = -28\\f^{(2)} (-2) = -3(3)2(-2) = -36\\f^{(2)} (-2) = -3(3)2 = -18$

$f(x) = {\displaystyle 8 + \frac{-28}{1}(x+2)+\frac{-36}{2!}(x+2)^2 + \frac{-18}{3!}(x+2)^2 }$

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2 years ago