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andrew-mc [135]
3 years ago
5

-2x+y=9 I need to isolate y

Mathematics
2 answers:
anygoal [31]3 years ago
7 0

Answer:

y =2x+9

Step-by-step explanation:

-2x+y=9

Add 2x to each side

-2x+2x+y=2x+9

y =2x+9

Ivanshal [37]3 years ago
6 0

Answer:

y = 2x + 9

Step-by-step explanation:

Add 2x to both sides.  You will immediately get y = 2x = 9.

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HELPPPP what do I do exactly ?
MAXImum [283]

Answer:


Step-by-step explanation:

Note that the squaring function and the square root function are inverses of one another.  If we make a list of perfect squares, we get {1, 4, 9, 16, 25, ...}.  Then the square roots of these numbers are {1, 2, 3, 4, 5, ... }.

Continue making a table of values to plot.  The first row has x=0, y=0; this reflects that the sqrt of 0 is 0.

Fill the first (x-) column with perfect squares and the second (y-) column with the square roots of these perfect squares:

x   y

0   0

1    1

4    2

9    3

and so on.

Now plot the following on the graph:  (1,1), (4,2), (9,3), ....  

Starting at (0,0) and moving to the right (indicating increases in x), plot these  points.  (You'll soon run out of room.)  Draw a smooth curve from (0,0) to connect these points.  The result is a graph of the square root function.

The domain of this function is "the set of all real numbers ≥0" and the range is the same:  "the set of all real numbers ≥0"

4 0
3 years ago
Read 2 more answers
Solving for matrices
muminat

Answer:

D

Step-by-step explanation:

The augmented matrix for the system of three equaitons is

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\5&2&-2&|&11\\5&-4&4&|&-7\end{array}\right)

Multiply the first row by 5, the second row by -3 and add these two rows:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\5&-4&4&|&-7\end{array}\right)

Subtract the third row from the second:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&6&-6&|&18\end{array}\right)

Divide the third row by 6:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&1&-1&|&3\end{array}\right)

Now multiply  the third equation by 26 and add it to the second row:

\left(\begin{array}{ccccc} 3&-4&-5&|&-27\\0&-26&-19&|&-168\\0&0&-45&|&-90\end{array}\right)

You get the system of three equations:

\left\{\begin{array}{r}3x-4y-5z=-27\\-26y-19z=-168\\-45z=-90\end{array}\right.

From the third equation

z=\dfrac{90}{45}=2.

Substitute z=2 into the second equation:

-26y-19\cdot 2=-168\\ \\-26y-38=-168\\ \\-26y=-168+38=-130\\ \\y=\dfrac{130}{26}=5.

Now substitute z=2 and y=5 into the first equation:

3x-4\cdot 5-5\cdot 2=-27\\ \\3x-20-10=-27\\ \\3x-30=-27\\ \\3x=-27+30=3\\ \\x=1.

The solution is (1,5,2)

4 0
3 years ago
Solve for w.<br> 40+4w=12w
Xelga [282]

Answer:

W=5

Step-by-step explanation:

40+4w=12w

-4w -4w

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÷8 ÷8

5=w

7 0
3 years ago
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Andrews [41]

Answer: a) 0 and 0.01 b) 0.99 and 1 c) 0.3 d) 0.6

Step-by-step explanation:

Probability is the likelihood that an event will occur. Probability values always lies between 0 and 1 0<P<1

A sure event occurs when the probability is 1 or values pretty close to 1 while probability of an impossible event is 0 or values close to 0. Looking at the given probability values, we can conclude that!

a) 0 and 0.01 = The event is impossible, it would never occur.

b) 0.99 and 1 - The event is certain, it would always occur.

c) 0.3 - The event is highly unlikely, but it will occur once in a while.

d) 0.6 - The event will occur more often than not.

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H = hours, so h is less than or equal to 5.
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3 years ago
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