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lorasvet [3.4K]
3 years ago
10

Let f(x) = x + 8 and g(x) = x2 - 6x - 7. Find f(g(2)).

Mathematics
1 answer:
OLga [1]3 years ago
3 0
If you have double functions, solve the one in the parentheses first.

in f(g(2)), solve g(2) first.

So, substitute 2 in the function.

g(x) = x^2 - 6x - 7

g(2) = 2^2 - 6(2) - 7 = -15

If you substitute -15 in f(g(2)), it becomes f(-15).

f(x) = x + 8

f(-15) = -15 + 8

f(-15) = -7

The answer for f(g(2)) is -7.
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What is the slope of the line in this graph?
Nina [5.8K]

The slope of the line 5/7.

How do i know this?

Well the slope of a line is considered as rise/run.

So we start at the beginning and then go up until the line intersects a corner again. Then we mark that down.

Go back to the beginning and count how many times it takes to reach the height of the intersected corner. So it is 5.

Then we go to the right until we reach the point. And it takes 7 squares to reach it, so the slope it 5/7.

Your welcome! :D

7 0
2 years ago
Please help!<br><br> Thank you!
Dafna1 [17]

Answer:

(-16,17)

Step-by-step explanation:

The answer for the and point D is negative 16, 17. how you will solve this is you would take them in point and the endpoint c. to find that x of D you will do negative 4 minus 8 this equals negative 12. what you will do next is you will take the negative 12 and added to -4. this is how you get negative 16. you will then find the y of D. to do this you will take negative 7 and subtract 5. this equals negative 12. you will then take the midpoint and do 5 + 12. this equals 17. Hope this helps!

6 0
2 years ago
SHOW YOU WORK TO BE MARKED BRAINLIEST!!!
Nimfa-mama [501]

Answer: x=65

Step-by-step explanation:

Set (2x + 2) equal to (3x-63) because they are the same angle.

(2x+2)=(3x-63)

Subtract 2x from 3x which gives u 1x or just x

Now u have 2=x-63

Add 63 to both sides so now u have x =65

Lemme know if u need help

3 0
3 years ago
Which expression is equivalent to 6X equals 10 X +20
Andrei [34K]
I think it’s 2(5x +10)
7 0
2 years ago
Three six-sided fair dice are rolled. The six sides of each die are numbered 1; 2; : : : ; 6. Let A be the event that the first
valkas [14]

Answer:

1.) [A, B, C]

2.) [A', B', C']

3.) [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

4.) A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

Step-by-step explanation:

If A is the event that the first die shows an even number, then A' is the event that first die DOES NOT show an even number.

If B is the event that the Second die shows and even number, then B' is the event that second die DOES NOT show an even number.

If C is the event that the third die shows an even number, then C' is the event that third die DOES NOT show an even number.

Hence, our possible events are A, A', B, B', C, C'.

For question 1, in the event that all three dice show and even number, the expression of the event = [A, B, C]

For question two, in the event that no die shows an even number, the expression of the event = [A', B', C']

For question 3,In the event that at least one die shows an odd number, the expression of the event = [A', B, C] or [A, B', C] or [A, B, C'] or [ A', B', C] or [A', B, C'] or [A, B', C'] or [A', B', C']

For question 4,in the event that at most two dice show odd numbers, the expression of the event = [A', B', C] or [A', B, C'] or [A, B', C'] or [A', B, C] or [A, B', C] or [A, B, C'] or [A, B, C]

6 0
2 years ago
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