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monitta
3 years ago
8

Please help I need it ASAP

Mathematics
1 answer:
Leya [2.2K]3 years ago
5 0

Answer:

A. 0.57

Step-by-step explanation:

150 did attend out of the two schools

200 did not

in total there are 350 students

200/350 is equal to 0.57142857

that rounded is 0.57

A is 0.57

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x = 420/11

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I NEED HELP PLS
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Eric made two investments:
klemol [59]

Answer:10

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Notice that investment Q’s value grows linearly while investment R’s value grows exponentially. In conclusion, investment R’s value will first exceed investment Q’s value in year number 10

3 0
3 years ago
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Prove that sin^2A/cos^2A + cos^2A/sin^2A = 1/cos^2A*sin^2A - 2
jenyasd209 [6]

Answer:

prove that:

Sin²A/Cos²A + Cos²A/Sin²A = 1/Cos²A Sin²A - 2

LHS = \frac{Sin^2A}{Cos^2A} + \frac{Cos^2A}{Sin^2A}

Cos

2

A

Sin

2

A

+

Sin

2

A

Cos

2

A

= \begin{lgathered}= \frac{Sin^4A + Cos^4A}{Cos^2A . Sin^2A}\\\\Using\: a^2 + b^2 = (a+b)^2 - 2ab\\\\a = Cos^2A \: \& \:b = Sin^2A\\\\= \frac{(Sin^2A + Cos^2A)^2 - 2Sin^2A Cos^2A}{Cos^2A Sin^2A} \\\\Sin^2A + Cos^2A = 1\\\\= \frac{1 -2Sin^2A Cos^2A}{Cos^2A Sin^2A}\end{lgathered}

=

Cos

2

A.Sin

2

A

Sin

4

A+Cos

4

A

Usinga

2

+b

2

=(a+b)

2

−2ab

a=Cos

2

A&b=Sin

2

A

=

Cos

2

ASin

2

A

(Sin

2

A+Cos

2

A)

2

−2Sin

2

ACos

2

A

Sin

2

A+Cos

2

A=1

=

Cos

2

ASin

2

A

1−2Sin

2

ACos

2

A

\begin{lgathered}= \frac{1}{Cos^2A Sin^2A} - 2\\\\= RHS\end{lgathered}

=

Cos

2

ASin

2

A

1

−2

=RHS

LHS=RHS

4 0
3 years ago
Read 2 more answers
If f(x) = <img src="https://tex.z-dn.net/?f=%5Cfrac%7Bx%2B3%7D%7B4%7D" id="TexFormula1" title="\frac{x+3}{4}" alt="\frac{x+3}{4}
natulia [17]

Answer:

option (b) is correct

inverse of function  f(x)=\frac{x+3}{4} is 4x+3

Step-by-step explanation:

Given function f(x)=\frac{x+3}{4}

We have to find the inverse of given function.

Let f(x) = y then taking inverse both sides, we get

f^{-1}(y)=f^{-1}(f(x))\\\\\ f^{-1}(y)=x

Substitute , x  and f(x) in given equation, we get,

f(x)=\frac{x+3}{4} \Rightarrow \frac{(f^{-1}(y))+3}{4}

Now solve for (f^{-1}(y)) , we get,

(f^{-1}(y))+3=4y

(f^{-1}(y))=4y-3

Thus, inverse of function  f(x)=\frac{x+3}{4} is 4x+3

Thus, option (b) is correct.

8 0
3 years ago
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