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liberstina [14]
2 years ago
12

Are these similar and please explain why or why not.

Mathematics
2 answers:
krok68 [10]2 years ago
5 0

Answer: no they are not simular and the reason for this is because not only are one of the sides off but one of the x values on the first one is not equal.

Step-by-step explanation:

I hope this helps have a good day

Elis [28]2 years ago
5 0

Answer:

Yes, they are similar.

Step-by-step explanation:

The two triangles have at least one angle that is the same.

(I am most definitely NOT sure about this one btw)

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the ratios of the sides of a triangle are 3:2:4. if the shortest side is 26cm, what is the length of the longest side?
zalisa [80]
Answer: 52

Divide 26/2 and you get 13, and then multiply 13 by 4. Think of it as a proportion.
4 0
3 years ago
How do you solve X+10y=-9 X=5y+21
oee [108]

Answer:

Step-by-step explanation:

4 0
3 years ago
Answer my math question I asked so many times I lost most of points
maks197457 [2]

Answer:

f(x) = (x+1)^2 - 9

7 0
2 years ago
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A person who is 1.5 meters tall casts a shadow that is 8 meters long. The distance along the ground from the person (N) to the f
neonofarm [45]
1.) 1.5m/8m= fg/32m
2.) 1.5 (32)= 8m * fg
3.) 1.5 (32)/8m= fg
4.) 6m = fg

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7 0
3 years ago
Find the vertex of the graph of the function.
lapo4ka [179]

Answer: The correct options are  (1) (5,10), (2) (3,-3), (3) x = -1, (4) y=(x+2)^2+3, (5) 21s and (6) 0, -1, and 5.

Explanation:

Te standard form of the parabola is,

f(x)=a(x-h)^2+k        .....(1)

Where,  (h,k) is the vertex of the parabola.

(1)

The given equation is,

f(x)=(x-5)^2+10

Comparing this equation with equation (1),we get,

h=5 and k=10

Therefore, the vertex of the graph is (5,10) and the fourth option is correct.

(2)

The given equation is,

f(x)=3x^2-18x+24

f(x)=3(x^2-6x)+24

To make perfect square add (\frac{b}{2a})^2, i.e., 9. Since there is factor 3 outside the parentheses, so subtract three times of 9.

f(x)=3(x^2-6x+9)+24-3\times 9

f(x)=3(x-3)^2-3

Comparing this equation with equation (1),we get,

h=3 and k=-3

Therefore, the vertex of the graph is (3,-3) and the fourth option is correct.

(3)

The given equation is

f(x)=4x^2+8x+7

f(x)=4(x^2+2x)+7

To make perfect square add (\frac{b}{2a})^2, i.e., 1. Since there is factor 4 outside the parentheses, so subtract three times of 1.

f(x)=4(x^2+2x+1)+7-4

f(x)=4(x+1)^2+3

Comparing this equation with equation (1),we get,

h=-1 and k=3

The vertex of the equation is (-1,3) so the axis is x=-1 and the correct option is 2.

(4)

The given equation is,

y=x^2+4x+7

To make perfect square add (\frac{b}{2a})^2, i.e., 2^2.

f(x)=x^2+4x+4+7-4

f(x)=x^2+4x+4+7-4

f(x)=(x+2)^2+3

Therefore, the correct option is  4.

(5)

The given equation is,

h=-16t^2+672t

It can be written as,

h=-16(t^2-42t)

It is a downward parabola. so the maximum height of the function is on its vertex.

The x coordinate of the vertex is,

x=\frac{b}{2a}

x=\frac{42}{2}

x=21

Therefore,  after 21 seconds the projectile reach its maximum height and the correct option is first.

(6)

The given equation is,

f(x)=3x^3-12x^2-15x

f(x)=3x(x^2-4x-5)

Use factoring method to find the factors of the equation.

f(x)=3x(x^2-5x+x-5)

f(x)=3x(x(x-5)+1(x-5))

f(x)=3x(x-5)(x+1)

Equate each factor equal to 0.

x=0,-1,5

Therefore, the zeros of the given equation is 0, -1, 5 and the correct option is 2.

3 0
3 years ago
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