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romanna [79]
3 years ago
7

There are 4 red die, 6 blue die, and 9 green die. What is the probabiltiy of selecting a green die?

Mathematics
2 answers:
m_a_m_a [10]3 years ago
5 0
Answer: 9/19

Explanation: add all the die to find the total amount (19) so we know that 9 of the 19 die a green, therefore to probability is 9/19
Lelu [443]3 years ago
5 0

Answer: 9 is very likely to be picked

Step-by-step explanation:

add all the die to find the total amount (19) so we know that 9 of the 19 die a green, therefore to probability is 9/19

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Factorise
Rufina [12.5K]

Answer:

6x - 9

3(2x−3)

2a(5b+3)

Step-by-step explanation:

Factor 6a+10ab

10ab+6a

Factor 6x−9

6x−9

=3(2x−3)

                             :))

8 0
3 years ago
Read 2 more answers
Mary has $267 in her checking account . She writes checks for $33,$65 and 112. What is the balance in her account now ?
natulia [17]

Answer:

57

Step-by-step explanation:

6 0
3 years ago
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GIVING BRAINLIEST!! HELP PLEASE!! you don't have to make it perfect. (no links/spam/or stealing points. i will report your accou
choli [55]
<h2>Answer:</h2>

C = 2πr

r = C/2π ...(1)

A = πr²

A = π(C/2π)² = πC²/4π²

A = C²/4π.

<u>Correct choice</u> - [A] A = C²/4π.

6 0
3 years ago
(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop
zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})

Compute the sample sizes as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}

       n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}

          =\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

\hat p_{1}=0.45\\\hat p_{2}=0.58

Compute the sample size as follows:

MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}

       n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}

          =\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666

Thus, the sample sizes are 6666.

7 0
3 years ago
There are six houses in a colony, such that 3 houses are in one row and the other 3 houses are in the opposite row. The three ho
Reil [10]

The GREEN house is diagonally opposite the orange-coloured house.

There are six houses in a colony, such that 3 houses are in one row and the other 3 houses are in the opposite row.

Each house is painted with a different colour from red blue, green,

yellow, pink and orange.

1. Houses at the corner are not painted in blue and red colour

2. House painted orange colour is not opposite the house painted in green colour

3. Yellow and pink coloured houses are not in the same row

We need to find which house is diagonally opposite the orange-coloured house

<h3>What is probability?</h3>

Probability can be defined as the ratio of the number of favourable outcomes to the total number of outcomes of an event. For an experiment having 'n' number of outcomes, the number of favourable outcomes can be denoted by x. The formula to calculate the probability of an event is as follows.

Probability(Event) = Favorable Outcomes/Total Outcomes = x/n

Arrangement is

Row1              1             2             3

Row2             4             5             6

Houses at the corner are not painted blue and red colour

1, 3, 4 & 6 are at the corner hence 2 and 5 has been Blue and Red in colour.

Blue = B , Red = R

Row1              1             B/R             3

Row2             4            R/B             6

House painted with orange colour is not opposite the house painted with green colour

Yellow and pink coloured houses are not in the same row

Also yellow and pink can not be opposite as then orange will be opposite to green

Hence yellow and pink are diagonally opposite

Hence green house is opposite to orange House

Row1              Y/P             B/R                G/O

Row2             O/G            R/B                 P/Y

or

Row1              O/G             B/R               P/Y  

Row2             Y/P            R/B                 G/O

The GREEN house is diagonally opposite the orange-coloured house.

To learn more about probability visit:

brainly.com/question/9793303.

#SPJ4

4 0
1 year ago
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