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garik1379 [7]
2 years ago
10

How many 1.4 meter sections of rope can be cut from a length of rope 6 meters long?

Mathematics
1 answer:
den301095 [7]2 years ago
4 0
8.4 you mupitly 1.4*6 you will get this answer plz mark brainlest 
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For each mile that Jason runs, Meagan runs 1/4 Mile farther. If Jason ran 6 miles,how far did Megan run ?
Darina [25.2K]
6/1 × 1/4 = 6/4
6/4 = 1 2/4 = 1 1/2
6 + 1 1/2 = 7 1/2
Meagan ran 7 1/2 miles.
8 0
3 years ago
What is 3 divided by 11/12
Lena [83]

Answer:

0.02272

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
Question 6
olga nikolaevna [1]
The answer to your question: 5 - 6t
why it’s saying for each number for 6 so what ever number times 6 is t
6 0
2 years ago
Which of the following is a solution of the system 2x + y = 9 and 3x + 5y = 19.​
Nezavi [6.7K]

2x+y=9

3x+5y=19

I will do this problem in 2 ways. I.)Substitution II.)Elimination

Solution I.) Substitution

We can subtract 2x from both sides in the first equation.

y=9-2x

Now we can substitute the y in the second equation with 9-2x

3x+5(9-2x)=19

-7x+45=19

-7x=-26

x=26/7

y=9-2(26/7)=11/7

Solution II.)Elimination

We can multiply both side of first equation by 5 to get a 5y in both equations.

10x+5y=45

Now because both are positive 5y we just need to do simple subtraction of the 2 equation, each side respectively.

(10x+5y)-(3x+5y)=45-19

7x=26

x=26/7

2*26/7+y=9

y=11/7

Ultimately you get the same answer, both are viable methods, some problems are faster with one method but I recommend mastering both since they are very useful.

4 0
2 years ago
Martin wants to use coordinate geometry to prove that the opposite sides of
romanna [79]

The correct answer is option A which is the distance between A and D will be  AD = \sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b.

<h3>What is coordinate geometry?</h3>

A coordinate plane is a 2D plane which is formed by the intersection of two perpendicular lines known as the x-axis and y-axis.

The formula utilised to find the distance between two points is;-

X = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2

We have the coordinates of the point A = (0, 0) and D is  (0, b).By applying the formula to find the distance between A and D.

AD = \sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b.

Therefore the correct answer is option A which is the distance between A and D will be  AD = \sqrt{(0-0)^2-(b-0)^2}=\sqrt{b^2}=b.

To know more about Coordinate geometry follow

brainly.com/question/18269861

#SPJ1

4 0
2 years ago
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