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TEA [102]
3 years ago
8

- Katrina practices violin 4 times per

Mathematics
1 answer:
Darina [25.2K]3 years ago
5 0
Katrina practices 4 hours a week.

Jeremy practices 2 hours and 15 minutes a week.

Answer Katrina practices more than Jeremy by 1 hour and 48 minutes
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Adam traveled out of town for a regional basketball tournament. He drove at a steady speed of 72.4 miles per hour for 4.62 hours
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Answer:

334.488

Step-by-step explanation:

I used a calculator lol

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Which vocabulary word best describes what has been circled in this expression?
motikmotik
<h3>Answer:  Coefficient</h3>

The coefficient is the number just to the left of, or in front of, the variable. It's being multiplied by the variable

Eg: 7x = 7 times x

4 0
3 years ago
A data set that includes the years in which your hometown team won championships would be classified as what type of data
Elenna [48]

Answer:

Interval

Step-by-step explanation:

The interval scale is guageable and data following this scale can be added and subtracted.

Years are values we can either subtract or minus so they fall under the interval scale.

Also, they have no absolute zero, which is a characteristic of the interval scale.

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3 years ago
Help hell help help gelp help
IgorC [24]
Just read what it says not that hard go to the left twice and go up 4 units.

Hope you have a good day
3 0
3 years ago
TV advertising agencies face increasing challenges in reaching audience members because viewing TV programs via digital streamin
choli [55]

Answer:

a) The 99% confidence interval would be given (0.523;0.577).

We are 99% confident that this interval contains the true population proportion.

b) n=\frac{0.55(1-0.55)}{(\frac{0.03}{2.58})^2}=1830.51  

And rounded up we have that n=1831

Step-by-step explanation:

Data given and notation  

n=2341 represent the random sample taken    

X represent the people that they have watched digitally streamed TV programming on some type of device

\hat p=0.55 estimated proportion of people that they have watched digitally streamed TV programming on some type of device  

\alpha=0.01 represent the significance level

Confidence =0.99 or 99%

z would represent the statistic for the confidence interval  

p= population proportion of people that they have watched digitally streamed TV programming on some type of device

The population proportion present the following distribution:

p \sim N (p, \sqrt{\frac{p(1-p)}{n}}

Part a) Confidence interval

The confidence interval would be given by this formula

\hat p \pm z_{\alpha/2} \sqrt{\frac{\hat p(1-\hat p)}{n}}

For the 99% confidence interval the value of \alpha=1-0.99=0.01 and \alpha/2=0.005, with that value we can find the quantile required for the interval in the normal standard distribution.

z_{\alpha/2}=2.58

And replacing into the confidence interval formula we got:

0.55 - 2.58 \sqrt{\frac{0.55(1-0.55)}{2341}}=0.523

0.55 + 2.58 \sqrt{\frac{0.55(1-0.55)}{2341}}=0.577

And the 99% confidence interval would be given (0.523;0.577).

We are 99% confident that this interval contains the true population proportion.

Part b) What sample size would be required for the width of a 99% CI to be at most 0.03 irrespective of the value of p??

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

And replacing into equation (b) the values from part a we got:

n=\frac{0.55(1-0.55)}{(\frac{0.03}{2.58})^2}=1830.51  

And rounded up we have that n=1831

8 0
4 years ago
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