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suter [353]
3 years ago
14

In a total-immersion measurement of a woman's density, she is found to have a mass of 63 kg in air and an apparent mass of 0.097

5 kg when completely submerged with lungs almost totally empty.
A. What mass, in kg, of water does she displace?
B. What is her volume in m^3?
C. What is her average density in kg/m^3?
D. If her lung capacity is 1.75 L, is she able to float without treading water with her lungs filled with air? Assume the density of air is 1.29 kg/m3.
Physics
1 answer:
kumpel [21]3 years ago
7 0

Answer:

Explanation:

A) mass of displaced water = loss of mass in water = 63 - .0975 = 62.9025 kg

B) her volume = volume of displaced water

= mass of displaced water / density of water = 62.9025 / 1000 m³.

= 62.9025 x 10⁻³ m³

C) her average density = her mass / her volume = 63 / 62.9025 x 10⁻³

= 1.00155 x 10³ kg / m³

D) lung capacity = 1.75 L = 1.75 x 10⁻³ m³

buoyant force created by air in the lungs = 1.75 x 10⁻³ ( 1000- 1.29 ) =  1.74 kg

As it is more than 0.0975 kg , the apparent weight  in water so woman will float in water .

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