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3 years ago

Pls help me with this one. will give brainliest

Physics

1 answer:

Dmitry [639]3 years ago

3 0

Answer:

Point A and c

Explanation:

you can know the t is the strongest at either pole of the magnet or closer to pole of the magnet as, which you can see A and C was closest

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Imagine that the light you observe from space is exhibiting a redshift. This would mean that the Universe is Choose one: A. trav

docker41 [41]

Answer: C. Expanding

Explanation:

When an object moves away from an observer, the light waves emitted by the object are stretched out making them have move towards the red end of the electromagnetic spectrum, where light has a longer wavelength. This phenomenon is known as the redshift (cosmological redshift). For most astronomical objects, the observed spectral lines are all shifted to longer wavelengths. It is caused solely by the expansion of the Universe and thus, the value of a redshift indicates the recession velocity of the expanding object, or its distance.

Redshift is opposed to the blueshift. Blue light wavelengths tend to be closer together hence blueshift light tends to be emitted from objects that are collapsing.

7 0

3 years ago

A patient is administered 20 mg of iodine-131. How much of this isotope will remain in the body after 40 days if the half-life f

igor_vitrenko [27]

The formula for half-life is:

$A_{final}=A_{initial}(\frac{1}{2})^{\frac{t}{h}}$

Where A is the amount of iodine-131 initially and after 40 days, t is time, h is half-life of the isotope. Let's plug in our values to the equation:

$A_{final}=20(\frac{1}{2})^{\frac{40}{8}=0.625g$

Therefore, the patient has 0.625 grams of iodine-131 after 40 days.

4 0

3 years ago

Two in-phase loudspeakers that emit sound with the same frequency are placed along a wall and are separated by a distance of 8.0

zloy xaker [14]

Answer: $278\ Hz$

Explanation:

Given

Distance between two speakers is 8 m

Man is standing 12 away from the wall

When the person moves 3 parallel to the wall

the parallel distances from the speaker become 4+3, 4-3

Now, the difference of distances from the speaker is

$\Delta d=\sqrt{12^2+(4+3)^2}-\sqrt{12^2-(4-3)^2}\\\Delta d=1.85\ m$

Condition for destructive interference is

$\Delta d=(2n-1)\dfrac{\lambda }{2}=(2n-1)\dfrac{\nu }{2f}\\\\\Rightarrow f=(2n-1)\dfrac{v}{2\Delta d}$

for second destructive interference; n=2

$\Rightarrow f=(2\times 2-1)\dfrac{343}{2\times 1.85}=278.10\approx 278\ Hz$

4 0

3 years ago

A motorist traveling at 12 m/s encounters a deer in the road 39 m ahead. If the maximum acceleration the vehicle’s brakes are ca

Vera_Pavlovna [14]

Answer:

Explanation:

Given

Motorcyclist speed=12 m/s

maximum acceleration $=-6 m/s^2$

distance=39 m

Let x be the distance traveled by motorist in his reaction time

therefore remaining 39-x will be traveled with $-6m/s^2$ acceleration

$v^2-u^2=2as$

s=39-x

v=0

u=12 m/s

$0-12^2=2\left ( -6\right )\left ( 39-x\right )$

x=27 m

Therefore he traveled 27 m in his reaction time

$27=12\times t$

t=2.25 s

(b)If his reaction time is 2.56 sec

then distance traveled in his reaction time

$x_0=12\times 2.56=30.72 m$

Remaining distance 39-30.72=8.28 m

therefore its velocity when it reaches the deer

$v^2-u^2=2as$

$v^2=12^2+2\times \left ( -6\right )\times 8.28=44.64$

v=6.681 m/s

8 0

4 years ago

Six moles of an ideal gas are in a cylinder fitted at one end with a movable piston. The initial temperature of the gas is 28.0

mel-nik [20]

Answer:

63.5 °C

Explanation:

The expression for the calculation of work done is shown below as:

$w=P\times \Delta V$

Where, P is the pressure

$\Delta V$ is the change in volume

Also,

Considering the ideal gas equation as:-

$PV=nRT$

where,

P is the pressure

V is the volume

n is the number of moles

T is the temperature

R is Gas constant having value = 8.314 J/ K mol

So,

$V=\frac{nRT}{P}$

Also, for change in volume at constant pressure, the above equation can be written as;-

$\Delta V=\frac{nR\times \Delta T}{P}$

So, putting in the expression of the work done, we get that:-

$w=P\times \frac{nR\times \Delta T}{P}=nR\times \Delta T$

Given, initial temperature = 28.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15

So,

T₁ = (28.0 + 273.15) K = 301.15 K

W=1770 J

n = 6 moles

So,

$1770\ J=6 moles\times 8.314\ J/ Kmol \times (T_2-301.15\ K)$

Thus,

$T_2=301.15\ K+\frac{1770}{6\times 8.314}\ K$

$T_2=336.63\ K$

The temperature in Celsius = 336.63-273.15 °C = 63.5 °C

<u>The final temperature is:- 63.5 °C</u>

7 0

4 years ago